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BigorU [14]
3 years ago
5

Hi!! Does anyone know this answer? :D

Physics
2 answers:
Agata [3.3K]3 years ago
8 0

Answer:

c seems to be the only reasonable answer

kondor19780726 [428]3 years ago
8 0

Answer:

Im not fully corrrect but I would say C

Explanation:

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Over a period of more than 30 years, albert klein of california drove 2.5 × 106 km in one automobile. consider two charges, q1 =
Semenov [28]
For q3 to be in equilibrium the total force acting on it has to be zero.
Let's say that total distance traveled by car is L (this is just for the convenience).
We can set up a system of equations to find an answer. Let's say that from q1 to q3 the distance is r_1 and from q3 to q2 the distance is r_2, we know that this distance has to be equal to:
r_1+r_2=L km
The second equation is going to the total force acting on the charge q3:
F_{q3}=F_{q3q1}+F_{q3q2}=0\\ 0=k_c\frac{q_1q_3}{r_1^2}+k_c\frac{q_3q_2}{r^2}
k_c is the Coulomb's constant. Since left-hand side is zero we just divide whole equation with k_c to get rid of it:
0=\frac{q_1q_3}{r_1^2}+\frac{q_3q_2}{r^2}
Let's solve this for r_1^2:
0=\frac{8}{r_1^2}+\frac{24}{r^2}\\ \frac{1}{r_1^2}=-\frac{3}{r^2}\\ r_1^2=-\frac{r^2}{3};r_2=L-r_1\\ r_1^2=\frac{(L-r_1)^2}{3}\\ r_1^2=\frac{L^2-2Lr_1+r_1^2}{3}\\ 3r_1^2=L^2-2Lr_1+r_1^2\\ 2r_1^2+2Lr_1-L^2=0
Now we have a quadratic equation with following parameter:
a=2\\ b=2L\\ c=-L^2
We know that two solutions are:
r_{1,\:2}=\frac{-b\pm \sqrt{b^2-4ac}}{2a}\\ r_{1,\:2}=\frac{-2L\pm \sqrt{4L^2+8L^2}}{4}\\ r_{1,\:2}=\frac{-2L\pm \sqrt{12L^2}}{4}\\
We need a positive solution. When we plug in all the numbers we get:
r_1=0.915\cdot 10^6$km

6 0
4 years ago
What are the three types of muscle fibers?
DiKsa [7]
Smooth,cardiac,invountary
6 0
3 years ago
Read 2 more answers
A snail can move approximately 0.30 meters per minute. How many meters can the snail cover in
Alexxx [7]
Distance = velocity (or speed) x time
so, distance = 0.30 meters.min x 15 mins
distance = 4.5 meters 
5 0
3 years ago
Read 2 more answers
Describe the trip from your home to school using the words position, distance, displacement, and
ozzi

Answer:

The position of my house is a little uphill as compared to the position of my school. The distance I have to travel from my house to school is nearly 2 kilometers. The displacement is in the 2000 m towards the left from my house. The speed of the bus which I usually take is 40 km/ hour.

6 0
3 years ago
A system of releases 125kJ of heat while 104kJ of work is done in the system. Calcilate the change om imternal energy (in kJ)
artcher [175]

Answer:

DU = 21 KJ

Explanation:

Given the following data;

Quantity of heat = 125 KJ

Work = 104 KJ

To find the change in internal energy;

Mathematically, the change in internal energy of a system is given by the formula;

DU = Q - W

Where;

DU is the change in internal energy.

Q is the quantity of energy.

W is the work done.

Substituting into the formula, we have;

DU = 125 - 104

DU = 21 KJ

4 0
3 years ago
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