Answer:
Part a)
Part b)
Ball thrown downwards =
Ball thrown upwards =
Part c)
Explanation:
Part a)
Since both the balls are projected with same speed in opposite directions
So here the time difference is the time for which the ball projected upward will move up and come back at the same point of projection
Afterwards the motion will be same as the first ball which is projected downwards
so here the time difference is given as
Part b)
Since the displacement in y direction for two balls is same as well as the the initial speed is also same so final speed is also same for both the balls
so it is given as
Part c)
Relative speed of two balls is given as
now the distance between two balls in 0.8 s is given as
Solution :
Speed of the air craft, 
= 262 m/s
Fuel burns at the rate of, 
= 3.92 kg/s
Rate at which the engine takes in air, 
= 85.9 kg/s
Speed of the exhaust gas that are ejected relative to the aircraft, 
=921 m/s
Therefore, the upward thrust of the jet engine is given by
F = 85.9(921 - 262) + (3.92 x 921)
= 4862635.79 + 3610.32
= 
Therefore thrust of the jet engine is .
Answer:
The magnification is a function of the lenses in the objective and the eyepiece, so the magnification of the two must be multiplied to obtain the total magnification possible. So, for example, if the objective lens was 4X and the eye piece lens was 10X, the total magnification would be 40. (4 x 10 = 40)
Explanation:
Force = work / dis
= 60/ 5
= 12 N
The answer is A for sure , hope it’s correct
