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Answer:
Maximum amount of heat = 10002151.38J
Explanation:
Workdone by motor in 86.1 minutes I given by:
W = power × time
W= 294 × 86.1×60
W= 1439424 Joules
W= 1.4 ×10^6Joules
The amount of heat extracted is given by:
/QL /= K/W/ = TL/W/ /(TH - TL)
Where TL= freezing compartment temperature
TH = Outside air temperature
/QL /= 271 × 1439424 / (310 - 271)
/QL/ = 390083904/39
/QL/ = 10002151.38 Joules
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It appears to be a <span>spiral shape. </span>