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Zielflug [23.3K]
2 years ago
11

Discuss how personal choice can enhance your safety when exercising.

Physics
2 answers:
anzhelika [568]2 years ago
8 0

Answer and explanation;

In general, you can choose when, where, and how to exercise. Each of these choices can either positively or negatively affect your safety during physical activity.

To play it safe and reduce your risk of injury: Begin your exercise program slowly with low-intensity exercises. Wear appropriate shoes for your activity. Warm up before exercising, and cool down afterward. Pay attention to your surroundings when exercising outdoors.

Lady_Fox [76]2 years ago
5 0

<span>In general, you can choose when, where, and how to exercise. Each of these choices can either positively or negatively affect your safety during physical activity.</span>

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The center of mass is
PolarNik [594]
D is the best answer. In many physics problems we treat an extended object as if it were a point with the same mass located at the center of mass.
5 0
3 years ago
a cone is constructed by cutting a sector from a circular sheet of metal with radius . the cut sheet is then folded up and welde
Svet_ta [14]

The expression for the radius and height of the cone can be obtained from

the property of a function at the maximum point.

  • The \ radius, \ of \ the \ base \ of \ the \ cone \ is \ \sqrt{ \dfrac{3}{4}} \times radius \ of \ circular \ sheet \ metal
  • The height of the cone is half the length of the radius of the circular sheet metal.

Reasons:

The part used to form the cone = A sector of a circle

The length of the arc of the sector = The perimeter of the circle formed by the base of the cone.

Volume \ of \ a \ cone = \dfrac{1}{3} \cdot  \pi \cdot r^3 \cdot h

  • Volume \ of \ a \ cone, \, V = \dfrac{1}{3} \cdot  \pi \cdot r^3 \cdot \sqrt{(s^2- r^2)}

θ/360·2·π·s = 2·π·r

Where;

s = The radius of he circular sheet metal

h = s² - r²

  • \dfrac{dV}{dr} = \dfrac{d}{dr}  \left(\dfrac{1}{3} \cdot  \pi \cdot r^3 \cdot \sqrt{(s^2- r^2)}\right) = \dfrac{\pi \cdot (3 \cdot r^2 \cdot  s^2 - 4 \cdot r^4)}{\sqrt{(s^2- r^2)}} = 0

3·r²·s² - 4·r⁴ = 0

3·r²·s² = 4·r⁴

3·s² = 4·r²

\underline{\left  \right. The \ radius, \, r =\sqrt{ \dfrac{3}{4}} \cdot s}

\underline{The \ height, \, h =\sqrt{s^2 - \dfrac{3}{4}\cdot s^2} = \dfrac{s}{2}}}

Learn more here:

brainly.com/question/14466080

3 0
2 years ago
block of mass 0.5kg on a horizontal surface is attached to a horizontal spring of negligible mass and spring constant 50N/m . Th
Alisiya [41]

Answer:

Explanation:

The mass of the block is 0.5kg

m = 0.5kg.

The spring constant is 50N/m

k =50N/m.

When the spring is stretch to 0.3m

e=0.3m

The spring oscillates from -0.3 to 0.3m

Therefore, amplitude is A=0.3m

Magnitude of acceleration and the direction of the force

The angular frequency (ω) is given as

ω = √(k/m)

ω = √(50/0.5)

ω = √100

ω = 10rad/s

The acceleration of a SHM is given as

a = -ω²A

a = -10²×0.3

a = -30m/s²

Since we need the magnitude of the acceleration,

Then, a = 30m/s²

To know the direction of net force let apply newtons second law

ΣFnet = ma

Fnet = 0.5 × -30

Fnet = -15N

Fnet = -15•i N

The net force is directed to the negative direction of the x -axis

8 0
3 years ago
Which of the following affect friction (you can choose more than 1)
Anastaziya [24]
I think it would be WEIGHT and ROUGHNESS OF SURFACE.
4 0
2 years ago
Read 2 more answers
What is the root mean square speed of an As4 particle as it is sublimed? (Assume at high temperatures arsenic acts like an ideal
Norma-Jean [14]

Answer: v_{rms} = 273m/s

Explanation: <u>Root</u> <u>Mean</u> <u>Square</u> <u>Speed</u> of an atom or molecule is the speed of a particle in a gas. It is the average speed a particle in a gas can have.

It can be calculated:

\frac{1}{2}mv^{2} = \frac{3}{2} k_{B}T

v^{2} = \frac{3k_{B}T}{m}

v = \sqrt{\frac{3k_{B}T}{m}}

m is mass of one atom or molecule in kg.

An atom of Arsenic sublimes at 614°C. Converting to Kelvin:

T = 614 + 273 = 887K

Molecular mass of As4 is approximately 0.3kg.

m = \frac{0.3}{6.10^{23}}

m=5.10^{-25}kg

Calculating Root mean square speed :

v = \sqrt{\frac{3*1.4.10^{-23}*887}{5.10^{-25}}

v = \sqrt{745.08.10^{2}

v = 273m/s

<u>The root mean square speed of As4 is approximately </u><u>273m/s</u><u>.</u>

5 0
3 years ago
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