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3 years ago

Which statement best describes the diagram please help

Chemistry

1 answer:

Gwar [14]3 years ago

3 0

Answer:

The right statement is " the Pathway A-C-D involves a catalyst and is faster than A-B-D"

Explanation:

Catalyst is a substance that increases the rate of a chemical reaction by lowering the activation energy Eₐ (i.e. by changing the reaction pathway), which Catalyst is not consumed in the catalyzed reaction and can continue to act repeatedly.

From the attached figure one can see that the path way A-C-D has different pathway and lower activation energy (Eₐ) than the pathway A-B-D, this means that the pathway A-C-D is a catalyzed pathway and it is faster than A-B-D.

So, the right statement is " the Pathway A-C-D involves a catalyst and is faster than A-B-D"

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What type of critial thinking is important in agriscience

nlexa [21]

Answer:

Explanation:

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2 years ago

How many liters of O₂ are needed to react completely with 10.0 L of H₂S at STP

sergiy2304 [10]

Ideal gas law is valid only for ideal gas not for vanderwaal gas. Therefore, 10L of H₂S should react with 6.6L of oxygen at stanadard pressure and temperature.

<h3>What is ideal gas equation?</h3>

Ideal gas equation is the mathematical expression that relates pressure volume and temperature.

Mathematically the relation between Pressure, volume and temperature can be given as

P×V=n×R×T

where,

P = pressure of gas

V= volume of gas

n =number of moles of gas

T =temperature of gas

R = Gas constant = 0.0821 L.atm/K.mol

At Standard temperature and pressure, 2 moles of H₂S react with 3 moles of 0₂. S0, 10L of H₂S should react with 0.66×10=6.6L of oxygen.

Therefore, 10L of H₂S should react with 6.6L of oxygen.

To learn more about ideal gas equation, here:

brainly.com/question/14826347

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7 0

1 year ago

How many unpaired electrons would you expect on iron in iron ii sulfide. enter an integer?

zimovet [89]

What are ur answers of the question

5 0

3 years ago

Read 2 more answers

If our eyes could see a slightly wider region of the electromagnetic spectrum, we would see a fifth line in the Balmer series em

erica [24]

Answer: Wavelength associated with the fifth line is 397 nm

Explanation:

$E=\frac{hc}{\lambda}$

$\lambda$ = Wavelength of radiation

E= energy

For fifth line in the H atom spectrum in the balmer series will be from n= 2 to n=7.

Using Rydberg's Equation:

$\frac{1}{\lambda}=R_H\left(\frac{1}{n_i^2}-\frac{1}{n_f^2} \right )\times Z^2$

Where,

$\lambda$ = Wavelength of radiation

$R_H$ = Rydberg's Constant = $10973731.6m^{-1}$

$n_f$ = Higher energy level = 7

$n_i$ = Lower energy level = 2 (Balmer series)

Putting the values, in above equation, we get

$\frac{1}{\lambda}=10973731.6\times \left(\frac{1}{2^2}-\frac{1}{7^2} \right )\times 1^2$

$\frac{1}{\lambda}=2.52\times 10^{6}m$

$\lambda}=3.97\times 10^{-7}m=397 nm$ $1nm=10^{-9}m$

Thus wavelength λ associated with the fifth line is 397 nm

7 0

4 years ago

how do i word a formal letter to a teacher saying i didn't pay attention during the science lessons and i now have no idea what

Allushta [10]

Explanation:

Hello mr/mrs (name) I unfortunately couldn't pay attention to the class due to some issues I had therefore I don't know what we are doing in class

Hello mr/mrs (name) I could understand what we were doing in class I would like it if you could break it down more or explain better to me

OR just say something it had something to do with your internet such as

Hello mr/mrs (name) I didn't understand what you were saying during our class due to some of my internet issues I was have throughout the day. I hope you can explain what we did during the class.

Those may be some of my excuses I've used before

they have worked for me:)

I don't know if that helped?:/

8 0

3 years ago