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2 years ago

When 1 carbon atom combines with 2 oxygen atoms, the resulting substance is called a(n) compoun

Chemistry

1 answer:

postnew [5]2 years ago

6 0

Carbon dioxide. 1 carbon is just carbon because you don’t put mono in-front. 2 oxygens is dioxide.

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The half-life of radioactive element krypton-91 is 10 seconds. if 16 grams of krypton-91 are initially present, how many grams a

earnstyle [38]

10 seconds = 8grams
then just divide by 2 another 4 times...
= 0.5grams after 50 seconds

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3 years ago

A chemical reaction that has a positive δg is correctly described as

Charra [1.4K]

Answer:

Endergonic reaction or nonspontaneous reaction.

Explanation:

Gibbs free energy is a state function that determines the spontaneity or feasibility of the given reversible chemical reaction, at fixed pressure and temperature. It is given by the equation:

ΔG = ΔH - TΔS

Here, ΔG - change in Gibbs free energy

ΔH- The change in enthalpy of reaction

ΔS - The change in entropy

T- Temperature

When the <u>change in the Gibbs free energy for a given reaction is positive</u> (ΔG > 0), then that chemical reaction is known as an endergonic reaction or nonspontaneous reaction.

4 0

2 years ago

In a simple covalent compound, which statement is TRUE

Savatey [412]

Answer:

C:to the right side of the periodic table, and it is given

the suffix -ide.

5 0

2 years ago

Which example describes how the water cycle carries on energy transfer? a flooding river depositing silt on a floodplain a warm

Irina18 [472]

Answer:

The water cycle is driven primarily by the energy from the sun. This solar energy drives the cycle by evaporating water from the oceans, lakes, rivers, and even the soil. Other water moves from plants to the atmosphere through the process of transpiration.

5 0

2 years ago

Read 2 more answers

How much ice (in grams) would have to melt to lower the temperature of 353 mL of water from 26 ∘C to 6 ∘C? (Assume the density o

Rashid [163]

Answer:

The mass of ice required to melt to lower the temperature of 353 mL of water from 26 ⁰C to 6 ⁰C is 85.4197 kg

Explanation:

Heat gain by ice = Heat lost by water

Thus,

Heat of fusion + $m_{ice}\times C_{ice}\times (T_f-T_i)=-m_{water}\times C_{water}\times (T_f-T_i)$

Where, negative sign signifies heat loss

Or,

Heat of fusion + $m_{ice}\times C_{ice}\times (T_f-T_i)=m_{water}\times C_{water}\times (T_i-T_f)$

Heat of fusion = 334 J/g

Heat of fusion of ice with mass x = 334x J/g

For ice:

Mass = x g

Initial temperature = 0 °C

Final temperature = 6 °C

Specific heat of ice = 1.996 J/g°C

For water:

Volume = 353 mL

$Density (\rho)=\frac{Mass(m)}{Volume(V)}$

Density of water = 1.0 g/mL

So, mass of water = 353 g

Initial temperature = 26 °C

Final temperature = 6 °C

Specific heat of water = 4.186 J/g°C

So,

$334x+x\times 1.996\times (6-0)=353\times 4.186\times (26-6)$

$334x+x\times 11.976=29553.16$

345.976x = 29553.16

x = 85.4197 kg

Thus,

<u>The mass of ice required to melt to lower the temperature of 353 mL of water from 26 ⁰C to 6 ⁰C is 85.4197 kg</u>

7 0

3 years ago