The solubility of a gas in water is 0.22 g/L at 20.0 kPa of pressure. What is the solubility when the pressure is increased to 1
1 answer:
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<u>Answer:</u> 72 grams of water will be produced.
<u>Explanation:</u>
To calculate the number of moles, we use the formula:
....(1)
Mass of propane = 44 grams
Molar mass of propane = 44 grams
Putting values in above equation, we get:
For the reaction of combustion reaction of propane, the equation follows:
By Stoichiometry of the reaction,
1 mole of propane produces 4 moles of water.
So, 1 mole of propane will produce = of water.
Now, to calculate the amount of water, we use equation 1, we get:
Molar mass of water = 18 g/mol
Mass of water produced = 72 grams
Hence, 72 grams of water will be produced.