The solubility of a gas in water is 0.22 g/L at 20.0 kPa of pressure. What is the solubility when the pressure is increased to 1
15 kPa?
1 answer:
Answer:
Solubility is 1.265g/L
Explanation:
According to Henry's law which states that the solubility of a gas in liquid is directly proportional to the pressure of the gas above the solution.
Sg1 / P1 = Sg2/ P2,
where Sg is the gas solubility, P is the gas pressure.
Sg1 = 0.22
P1 = 20kPA
P2 = 115kPA
Sg2 =?
Sg2 = Sg1 P2 / P1
Sg2 = 0.22 * 115*10^3 / 20*10^3
Sg2 = 25.3*10^3 / 20*10^3
Sg2 = 1.265g/L
the solubility of the gas in water at the new pressure is 1.265g/L
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