Let the number<span> be H T O. Ones digit = O Given that. O =10−5 ⇒ O =5. Also is given that tens digit T is 2 </span>more than<span> ones digit O ⇒ tens digit T = O +2=5+2=7. ∴ The </span>number<span> is. H 75. Given also is that "</span>number<span> is </span>less<span> than </span>200<span> and </span>greater than 100<span> " ⇒ H can take value only =1. We get our </span>number<span>as 175.</span>
3x = x / 2
Mmc (2,1) = 2
6x = x
6x- x = 0
5x= 0
x = 0/5
x = 0
Find a common denominator. The lowest one would come from you multiplying 2/5 by 4 on each side and 1/4 by 5 on each side. You are left with 8/20 and 5/20, added together would be 13/20.
x² = 6x - 9, or x² - 6x + 9 = 0, or x² - 2*x*3 + 3² = 0, or (x-3)² = 0 => x₁ = x₂ = 3.
Green eyes.
