The formula for GPE is PE=mgh, where “m” is the mass of the object, “g” is the acceleration due to gravity (~9.8 m/s^2 on Earth’s surface), and “h” is the height of the object from the ground. Therefore,
PE=mgh
PE=(6 kg)(9.8 m/s^2)(1 m)
PE=58.8 kg•m^2/s^2 or 58.8 Newtons
The GPE of the bowling ball under these conditions would be about 59 Newtons.
Hope this helps!
In this item, I supposed, that we are determine the molar fraction of oxygen and carbon dioxide in the sample. This can be done by dividing their respective partial pressures by the total pressure of the sample.
O2 : mole fraction = (100.7 mmHg) / (763.00 mmHg) = 0.13
CO2 : mole fraction = (33.57 mmHg) / (763.00 mmHg) = 0.044
Answers: O2 = 0.13
CO2 = 0.044
The term "valence electrons" refers to all of the electrons in an atom's outermost shell.
The centre of the atom is where the nucleus is. The nucleus contains protons and neutrons. The electrons travel in a specific circular direction and at a specific distance from the nucleus.
The atom's final shell's electrons take part in chemical reactions and the production of bonds. Both ionic and covalent bonding involve valence electrons. Metals are elements with one, two, or three electrons in their final shell.
These substances become positive ions after losing their electrons. Non-metals are substances with 5, 6, or 7 electrons in the outermost shell. These substances all gain electrons and change into negative ions.
Ionic bonds are those created by the transfer of electrons between metals and non-metals. For instance, ionic bonding allows sodium and chlorine to interact to generate sodium chloride.
To know more about valence electrons here
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Answer: options B,D and F
Explanation:
Since redox reactions are those which involves both oxidation and reduction
In B , Cu is oxidized and S gets reduced
D, Na gets oxidized and hydrogen gets reduced
F, carbon gets oxidized and Oxygen gets reduced
In g, there is no change in oxidation no of s in both product and Reactants is same +4
Similarly in the case of Ag and Mg.