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Zielflug [23.3K]
3 years ago
11

Find the domain of the function 

Mathematics
1 answer:
densk [106]3 years ago
4 0

Answer:

3x - 7 ≥ 0

3x ≥ 7

x ≥ 7/3

D = [7/3 ; ∞[

D = [7/3 ; ∞)

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What is y=8.5x contasnt of proportionality
Setler79 [48]

The constant of proportionality represents the unit cost .You use the equation y = 8.5 x to calculate the total cost y in dollars for x in what ever you are buying
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3 years ago
PLEASE HELP ASAP !!!!!!
ser-zykov [4K]

You should try to add 4 and place the 2 in the 3 digit slot

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PLZ HELP BRAIN FAM!!!
RideAnS [48]
It would be 7.45 since the -3.05 and the -9.5 together would equal -12.55 which subtracted from 20 would equal 7.45
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3 years ago
Read 2 more answers
Apples sell for $1.90 per pound, and bananas sell for $0.75 per pound. Troy bought some apples and some bananas. Together they w
matrenka [14]

Answer:

1.15p + 285 = 5.84

Step-by-step explanation:

This problem has two equations. Total cost and Total pounds. The cost and the pounds

p = apple pounds

b = banana pounds

<u>Cost</u>

1.90p + .75b =  5.84

<u>Pounds</u>

p + b = 3.8

<u>Now we use the substitute method for system of equations to solve</u>

p + b = 3.8

b = -p + 3.8

<u>Now that we know what b equals, substitute is for b in the cost equation.</u>

1.90p + .75b =  5.84

1.90p + .75(-p+3.8) =  5.84

<u>distribute / multiply  .75 by (-p+3.8)</u>

1.90p +  -.75p + 2.85 =  5.84

<u>Combine the p values</u>

1.15p + 285 = 5.84

4 0
3 years ago
What is the length of the conjugate axis?<br> <img src="https://tex.z-dn.net/?f=%5Cfrac%7B%28x-2%29%5E2%7D%7B36%7D%20-%20%5Cfrac
LuckyWell [14K]

Answer:

the length of the conjugate axis  is 16

Step-by-step explanation:

We know that the general equation of a hyperbola with transverse horizontal axis has the form:

\frac{(x-h)^2}{a^2} - \frac{(y-k)^2}{b^2} = 1

Where the point (h, k) are the coordinates of the center of the ellipse

2a is the length of the transverse horizontal axis

2b is the length of the conjugate axis

In this case the equation of the ellipse is:

\frac{(x-2)^2}{36} + \frac{(y+1)^2}{64} = 1

Then

b^2 = 64\\\\b = \sqrt{64}\\\\b = 8\\\\2b = 16

Finally the length of the conjugate axis is 16

5 0
3 years ago
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