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Angelina_Jolie [31]
3 years ago
6

__________ was the first African American to earn a doctoral degree in psychology from a university in the US and is considered

the father of African American psychology. A. Richard Suinn B. Kenneth Clark C. J. Henry Alston D. Francis C. Sumner Please select the best answer from the choices provided A B C D
Physics
2 answers:
Vera_Pavlovna [14]3 years ago
7 0

Answer:

J. Henry Alston

Explanation:

qwelly [4]3 years ago
4 0
The answer is Francis Sumner
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Find the transformation matrix that rotates a rectangular coordinate system through an angle of 60 about axes equal angels with
RSB [31]

Answer:

  M = \left[\begin{array}{ccc}cos \ 60&0\\0&-sin \ 60\end{array}\right]

Explanation:

To find the matrix, let's decompose the vectors, the rotated angle is (-60C) for the prime system

          x ’= x cos (-60)

          y ’= y sin (-60)

we use

          cos 60 = cos (-60)

          sin 60 = - sin (-60)

we substitute

          x ’= x cos 60

          y ’= - y sin 60

the transformation system is

         \left[\begin{array}{ccc}x'\\y'\end{array}\right] = \left[\begin{array}{ccc}cos 60&0\\0&-sin60\end{array}\right] \ \left[\begin{array}{ccc}x\\y\end{array}\right]x '

the transformation matrix is

       M = \left[\begin{array}{ccc}cos \ 60&0\\0&-sin \ 60\end{array}\right]

4 0
3 years ago
A circular loop of wire with 15 turns, radius 0.129 m and resistance 0.251 Ohms is connected to a 16.7 V power supply. The magne
Licemer1 [7]

The magnetic field at the center of the circular loop is 3.24 x 10⁻⁴ T.

<h3>Current in the wire</h3>

The current in the wire is calculated as follows;

V = IR

I = V/R

I = 16.7/0.251

I = 66.53 A

<h3>Magnetic field at the center of the loop</h3>

The magnetic field at the center of the circular loop is calculated as follows;

B = \frac{\mu_0 I}{2R} \\\\B = \frac{4\pi \times 10^{-7} \times66.53 }{2\times 0.129} \\\\B = 3.24 \times 10^{-4} \ T

Learn more about magnetic field here: brainly.com/question/7802337

3 0
2 years ago
→Fo
irakobra [83]

Answer:

The mass of the block, M =T/(3a +g)  Kg

Explanation:

Given,

The upward acceleration of the block a = 3a

The constant force acting on the block, F₀ = Ma = 3Ma

The mass of the block, M = ?

In an Atwood's machine, the upward force of the block is given by the relation

                                     Ma = T - Mg

                                      M x 3a = T - Ma    

                                    3Ma + Mg = T

                                       M = T/(3a +g)  Kg

Where 'T' is the tension of the string.

Hence, the mass of the block in Atwood's machine is, M = T/(3a +g)  Kg

3 0
3 years ago
Read 2 more answers
What is the velocity of an object that has been in free fall for 2.5 s?
zvonat [6]

Answer: D. 25 m/s Downward

Explanation:

V = (g)(t)

V = (9.8 m/s²)(2.5)

V = 24.5 m/s

8 0
3 years ago
Vector ⃑ has a magnitude of 9.0 m and points 40° east of north. Vector ሬ⃑ has a magnitude of 15.0 m and points 30° north of west
Aleks [24]

Answer:

i actually dont know

Explanation:

im no brained

3 0
3 years ago
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