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dimulka [17.4K]
3 years ago
7

If a liquid is sealed in a container and kept at a constant temperature

Physics
1 answer:
Zarrin [17]3 years ago
5 0
<span>The complete question is:

</span><span>If a liquid is sealed in a container and kept at constant temperature, how does its vapor pressure change

</span>a. it continues to steadily increase 
<span>b. it increases at first, then remains constant </span>
<span>c. it increaees at first, then decreases </span>
<span>d. it continues to steadily decrease
</span>
I believe the correct answer is option B. The vapor pressure change would be that it  increases at first, then remains constant. <span>More particles escape the liquid and go into the vapor phase at first. But eventually, the number of escaping particles equals the number of particles going back into the liquid.</span>
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A) experiment. Is the answer.

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Observation is what you see and record during the experiment.

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A teacher performing a demonstration finds that a piece of cork displaces 44.5ml of water. The piece of cork has a mass of 11.1g
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Explanation:

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3 years ago
Two speedboats can each travel at V= 5 m/s with respect to water. One boat crosses the
charle [14.2K]
Consider the travel of the speedboat from A to B and back.
Refer to the first figure.
The boat travels at 5 m/s relative to the water, and the downstream speed of the water is 0.5 m/s.
Therefore,
V₁=5 m/s, u = 0.5 m/s, sinθ = 0.5/5 = 0.1 => θ = arcsin(0.1) = 5.74°.
The boat should travel upstream at 5 m/s, at an angle of 5.74°.

Similarly, return speed from B to A is 5 m/s, at 5.74° upstream.

The horizontal component of velocity from A to B (or vice versa) is 
5cos(5.74°) = 4.975 m/s.

The time required to travel 1000 m is
1000/4.975 = 202.02  = 3.367 min.
The time for the return trip is
t₁ = 2*3.367 = 6.734 min.

Consider travel from C to D and back, as shown in the second figure.
The resultant velocity upstream from C to D is
V₁ = 5 - 0.5 = 4.5 m/s
The time required to travel 1000 m fromC to D is
1000/4.5 = 222.22 s

The resultant velocity downstream from D to C is
V₂ = 5 + 0.5 = 5.5 m/s
The time required to travel fro D to C is 
1000/5.5 = 181.82 s
Total time for the return trip between C and D is
t₂ = 222.22 + 181.82 = 404.04 s = 6.734 min

Answer:
The first boat should travel upstream at an angle of 5.74°. The time for the return trip between A and B is t₁ = 6.734 min or 404.04 s.

The second boat travels upstream against the current, and downstream with the current. The time for the return trip between C and D is t₂ = 6.734 min or 404.04 s.

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3 years ago
A circle has radius of 10cm what is the area in m square. with explantion​
Aleks04 [339]

Answer:20

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