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Kruka [31]
4 years ago
15

Which term best describes a test used to answer a question?

Physics
1 answer:
Anastasy [175]4 years ago
3 0

A) experiment. Is the answer.

hypothesis is the educated guess about what the result of the experiment is before conducting the experiment.

Observation is what you see and record during the experiment.

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When point charges q = +8.4 uC and q2 = +5.6 uC are brought near each other, each experiences a repulsive force of magnitude 0.6
Bezzdna [24]

Answer:

Distance between the charges, r = 0.8 meters

Explanation:

Given that,

Charge 1, q_1=+8.4\ \mu C=+8.4\times 10^{-6}\ C

Charge 2, q_2=+5.6\ \mu C=+5.6\times 10^{-6}\ C

Repulsive force between charges, F = 0.66 N

Let r is the distance between charges. The formula for the electrostatic force is given by :

F=k\dfrac{q_1q_2}{r^2}

r=\sqrt{\dfrac{kq_1q_2}{F}}

r=\sqrt{\dfrac{9\times 10^9\times 8.4\times 10^{-6}\times 5.6\times 10^{-6}}{0.66}}

r = 0.8009 meters

or

r = 0.8 meters

So, the distance between the charges i 0.8 meters. Hence, this is the required solution.

4 0
3 years ago
What problim in flywheel
Gwar [14]

Answer:

There are several tell-tale signs that there is a problem with either the starter or flywheel that is preventing your car from starting or causing starting issues. Free spinning is when, for some reason, the starter gear is just spinning without contacting anything. The sound is similar to that of a small drill spinning.

please can u mark me as branliest

hope u liked my answer x

8 0
4 years ago
Two particles move along an x axis. The position of particle 1 is given by x ! 6.00t 2 # 3.00t # 2.00 (in meters and seconds); t
s344n2d4d5 [400]

Answer:

15.6m/s

Explanation:

V1=\frac{dx}{dt}=\frac{d}{dt}(6t^{2}+3t+2) because the derivate of the position is the velocity

V1=12t+3

V2=20+\int\limits^_ {} \,-8t because the integral of the acceleration is the velocity

V2=20-4t^{2}

V1=V2 to see when the velocities of particles match

12t+3=20-4t^2

4t^2+12t-17=0 we resolve this with \frac{-b+-(\sqrt{b^{2} -4ac} )}{2a}

and we take the positif root

t=1.05 sec

if we evaluate the velocity (V1 or V2) the result is 15.6m/s

7 0
3 years ago
A 10 kg dog runs across the ground and jumps onto an ice-covered pond at 5 m/s. If the force of friction acting on the dog is 8
zzz [600]

Answer:

15.625m

Explanation:

Using the equation of motion

v² = u²+2as

u and v are the initial and final velocities

a is the acceleration

s is the distance

Get the acceleration

According to Newton's second law;

F  = ma

8 = 10a

a = 8/10

a = 0.8m/s²

We are also given

v = 5m/s

u = 0m/s

Substitute into the formula above

v² = u²+2as

5² = 0²+2(0.8)s

25 = 1.6s

s = 25/1.6

s = 15.625m

Hence the dog will cover a distance of 15.625m before coming to rest

3 0
3 years ago
Draw a diagram showing 2 forces acting on an object in opposite directions with a total net force of 3N to the left.
andriy [413]

Answer:

hope it helps u ........

6 0
3 years ago
Read 2 more answers
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