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Ratling [72]
3 years ago
9

The graph represents the change in that occurs when food is cooked over a charcoal grill. Which statement correctly explains the

graph?
A. The reactants are unlit charcoal that has already released its energy, and the products are charcoal that has already burned.
B. The reactants are charcoal that has already burned and released its energy, and the products are unlit charcoal.
C. The reactants are unlit charcoal, and the products are charcoal that has already burned and released its energy.
D. The reactants are charcoal that has already burned, and the products are unlit charcoal that has already released its energy.

Physics
1 answer:
MArishka [77]3 years ago
6 0

<u>O</u><u>p</u><u>t</u><u>i</u><u>o</u><u>n</u><u> </u><u>C</u><u> </u><u>i</u><u>s</u><u> </u><u>t</u><u>h</u><u>e</u><u> </u><u>a</u><u>n</u><u>s</u><u>w</u><u>e</u><u>r</u>

<h3 /><h3><em>S</em><em>m</em><em>a</em><em>l</em><em>l</em><em> </em><em>Explanation</em><em>:</em><em>-</em></h3>

The reactants are charcoal that is unlit + oxygen and the products are the burnt charcoal + energy.

(Explanation with formula and reason attached. Check it.)

> Benjemin360

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\rm 9.186\times 10^{-7}\ C.

Explanation:

<u>Given:</u>

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When the dimensions of the plate of the capacitor is comparatively much larger than the distance of separation between the plates, then, according to the Gauss' law of electrostatics, the value of the electric field strength in the region between the plates of the capacitor is given by

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For the minimum value of electric field that produces spark,

\rm E = \dfrac{q}{A\epsilon_o}\\\Rightarrow q = E\ A\epsilon_o\\=3\times 10^6\times 3.46\times 10^{-2}\times 8.85\times 10^{-12}\\=9.186\times 10^{-7}\ C.

It is the maximum value of the magnitude of charge which can be added up to each of the plates of the capacitor.

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