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JulijaS [17]
3 years ago
15

"What is the magnifying power of an astronomical telescope using a reflecting mirror whose radius of curvature is 5.9 m and an e

yepiece whose focal length is 2.7 cm
Physics
1 answer:
notka56 [123]3 years ago
4 0

Answer:

The Magnifying power of a telescope is M = 109.26

Explanation:

Radius of curvature R = 5.9 m = 590 cm

focal length of objective f_{objective} = \frac{R}{2}

⇒ f_{objective} = \frac{590}{2}

⇒ f_{objective} = 295 cm

Focal length of eyepiece f_{eyepiece} = 2.7 cm

Magnifying power of a telescope is given by,

M = \frac{f_{objective} }{f_{eyepiece} }

M = \frac{295}{2.7}

M = 109.26

therefore the Magnifying power of a telescope is M = 109.26

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<h3>The types of circuit.</h3>

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<h3>What is a parallel circuit?</h3>

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Mathematically, the equivalent capacitance (C_{eq}) of an electrical circuit containing four capacitors which are connected in parallel is given by this formula:

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Substituting the given parameters into the formula, we have;

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Read more equivalent capacitance here: brainly.com/question/27548736

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3 0
2 years ago
as the trait is dominant and controlled by a single gene,the mutation must have occurred on both diploid copies. true or false?
GenaCL600 [577]

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False

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Therefore , as the trait is dominant and controlled by a single gene,the mutation must have occurred on both diploid copies is a false statement.

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