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Sedbober [7]
3 years ago
12

Three m^3 of air in a rigid, insulated container fitted with a paddle wheel is initially at 295 K, 200 kPa. The air receives 154

6 kJ of work from the paddle wheel. Assuming the ideal gas model, determine for the air the mass, in kg, final temperature, in K, and the amount of entropy produced, in KJ/K

Physics
1 answer:
nasty-shy [4]3 years ago
3 0

Answer:

1. 7.08Kg

2. 311K

3. 0.268KJ/K

Explanation:

See attached file

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Beginning at the NW corner of the intersection of Pine & 675, thence north 950 feet, thence west 380 feet, thence south 950
Serjik [45]

Answer:

this description is valid for mediadle displacement, bone is an acceptable description

Explanation:

The description of a person's position must be done with a position vector. These vectors must have magnitude, a given direction and a starting point.

In the description this has a starting point corner NO of pine and 675.

Each displacement occurs with respect to the previous one, indicating the magnitude of the displacement and its direction.

After analyzing  this description is valid for mediadle displacement, bone is an acceptable description

6 0
3 years ago
10. Heat is the transfer of thermal energy from one object to another because of a difference in
stiv31 [10]

Answer:

Temperature

Explanation:

Heat only flows from one point to the other due to the difference in temperature.

7 0
3 years ago
A coin is dropped in a 15.0 m deep well.
labwork [276]

Answer:

t = 1.75

t = 0.04

Explanation:

a)

For part 1 we want to use a kenamatic equation with constant acceleration:

X = 1/2*a*t^2

isolate time

t = sqrt(2X / a)

Plugin known variables. Acceleration is the force of gravity which is 9.8 m/s^2

t = sqrt(2*15m / 9.8m/s^2)

t = 1.75 s

b)

The speed of sound travels at a constant speed therefore we don't need acceleration and can use the equation:

v = d / t

isolate time

t = d / v

plug in known variables

t = 15m / 340m/s

t = 0.04 s

7 0
2 years ago
The spool has a mass of 50 kg and a radius of gyration of ko = 0.280 m. if the 20-kg block a is released from rest, determine th
Rzqust [24]
V₁ = (1/g)₁ = Way₁ = 20(9.81)(0) = 0
V₂ (Vg)₂ = -WAy₂ = -20(9.81)(0.5) = -98.1J
The kinetic energy because the pool rotates about a fixed axis 
W = VA/rA = VA/0.2 5VA
Mass momen of inertila about fixed axis which passes through point 0
I₀ = mko² = 50(0.280)² = 3.92 kg. m²
∴ The kinetic energy of the system is 
T = 1/2 I₀w² + 1/2mAVA²

= 1/2(3.92)(5VA)² + 1/2 (20) VA² = 59VA²
Now that the system is at rest then T₁ = 0
Energy conservation  is
T₁ +V₁ = T₂ + V₂
0+ 0 = 59VA² + (-98.1)
VA = 1.289 m/s
= 1.29 m/s
5 0
3 years ago
Why are all the​ noncurrent-carrying metal parts bonded together in a wiring​ system?
Yuliya22 [10]

Explanation:

This process is called Bonding and it is done to provide low resistance path to ground.

"Bonding — a low impedance direction achieved by permanently connecting all non-current-carrying metal parts to maintain electrical stability and to be able to conduct any current that is likely to be put on it safely.

6 0
3 years ago
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