If a simple truss member is known to carry a tensile force, then the internal force drawn on a free-body at a section cut when u
sing the method of sections is Group of answer choices a) pointed away from and perpendicular to the member. b) pointed toward and parallel to the member. c) pointed toward and perpendicular to the member. d) pointed away from and parallel to the member.
1 answer:
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Answer:
B = 8.0487mT
Explanation:
To solve the exercise it is necessary to take into account the considerations of the Magnetic Force described by Faraday,
The magnetic force is given by the formula
Where,
B = Magnetic Field
I = Current
L = Length
Angle between the magnetic field and the velocity, for this case are perpendicular, then is 90 degrees
According to our data we have that
I = 16.4A
F = 0.132N/m
As we know our equation must be modificated to Force per length unit, that is
Replacing the values we have that
Solving for B,
Answer:
K = 1.29eV
Explanation:
In order to calculate the kinetic energy of the proton you first take into account the uncertainty principle, which is given by:
(1)
Δx : uncertainty of position = 2.0pm = 2.0*10^-12m
Δp: uncertainty of momentum = ?
h: Planck's constant = 6.626*10^-34 J.s
You calculate the minimum possible value of Δp from the equation (1):
The minimum kinetic energy is calculated by using the following formula:
(2)
m: mass of the proton = 1.67*10^{-27}kg
in eV you have:
The kinetic energy of the proton is 1.29eV