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Svetradugi [14.3K]
3 years ago
5

Engineers are designing a curved section of a highway. If the radius of curvature of the curve is 173 m, at what angle should th

e curve be banked so that a car traveling at 29.0 m/s will stay on the road without the aid of frictional forces?

Physics
1 answer:
egoroff_w [7]3 years ago
8 0

Answer: The angle Ø = 26

Explanation:

The weight and the normal force of the road are the only two external forces acting on the car. A frictionless surface can only exert a force that is perpendicular to the surface. This is a normal force.

Since the car does not leave the surface of the road, the vertical components of the two external forces must be equal in magnitude and opposite in direction. Whereas ;

Horizontal component = centripetal force. While

The vertical component = Mg

Revolving the two components gives: tanØ = V^2/rg

Please find the attached file for the solution

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An antelope moving with constant acceleration covers the distance 70.0 m between two points in time 6.60 s. Its speed as it pass
Veronika [31]

Answer:

A) The speed at the first point is 6.91 m/s.

B) The acceleration is 1.12 m/s²

Explanation:

The equations of velocity and position of the antelope will be as follows:

x = x0 + v0 · t + 1/2 · a · t²

v = v0 + a · t

Where:

x = position of the antelope at time t

x0 = initial position

v0 = initial velocity

t = time

a = acceleration

v = velocity at time t

A) If we place the origin of the frame of reference at the first point, we can say that at t = 6.60 the position of the antelope is 70.0 m and its velocity is 14.3 m/s. In this way, we will have 2 equations with 2 unknowns, the initial velocity (the velocity at the first point) and the acceleration.

Let´s start finding the speed at the first point:

v = v0 + a · t       (solving for "a")

(v - v0)/t = a

Replacing a = (v - v0)/t  in the equation of the position:

x = x0 + v0 · t + 1/2 · (v - v0)/t · t²             (x0 = 0)

x = v0 · t  + 1/2 · v · t - 1/2 · v0 · t

x - 1/2 · v · t = 1/2 · v0 · t

2/t · (x - 1/2 · v · t) = v0

2/6.60 s · (70.0 m - 1/2 · 14.3 m/s · 6.60s) = v0

v0 = 6.91 m/s

The speed at the first point is 6.91 m/s.

B) Using the equation of velocity

a = (v - v0)/t

a = (14,3 m/s - 6.91 m/s) / 6.60 s

a = 1.12 m/s²

The acceleration is 1.12 m/s²

4 0
3 years ago
If you double both the current and the voltage in a circuit, the power _______. View Available Hint(s) If you double both the cu
EastWind [94]

Answer:

power will be quadruples    

Explanation:

We know that power in circuit is given by P = VI ,here V is voltage and I is current

Now according to question if we double the voltage and current then power

P will be P _{new}= 2V\times 2I = 4 VI = 4P

As we know that power is given by P = VI

So new power will be 4 P

So power will be quadruples

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Answer:

Meteorology

Explanation:

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