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Svetradugi [14.3K]
3 years ago
5

Engineers are designing a curved section of a highway. If the radius of curvature of the curve is 173 m, at what angle should th

e curve be banked so that a car traveling at 29.0 m/s will stay on the road without the aid of frictional forces?

Physics
1 answer:
egoroff_w [7]3 years ago
8 0

Answer: The angle Ø = 26

Explanation:

The weight and the normal force of the road are the only two external forces acting on the car. A frictionless surface can only exert a force that is perpendicular to the surface. This is a normal force.

Since the car does not leave the surface of the road, the vertical components of the two external forces must be equal in magnitude and opposite in direction. Whereas ;

Horizontal component = centripetal force. While

The vertical component = Mg

Revolving the two components gives: tanØ = V^2/rg

Please find the attached file for the solution

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What of the following is the mathematical form of boyles law?
viva [34]

Answer:

C

Explanation:

V=1/p

By means of cross multiplication so by that we will have pv=1 which also implies p1v1=p2v2 coz boyles law states that the volume of a given mass of gas is inversely proportional to pressure provided that the temperature in kelvin remains constant

7 0
3 years ago
Thomas and John are carrying a 43kg cylinder head on a 510cm X 510mm board. The cylinder head with dimensions of 43cm X 250mm li
tatyana61 [14]

John carry the heaviest load.

<h3>How to find out who is carrying the heavy load?</h3>

Write down given data from questions:

Board=510cm X 510mm.

Cylinder head with dimensions=43cm X 250mm.

Cylinder lies across the board 210cm from john.

Find out: Who is carry the heaviest load?​

Calculation:

We assume that mass of cylinder head = x kg

Then weight=x x 9*81

                 W=9.81x  Newton.

Weight per unit length= Weight/Total leanth

Weight per unit length= 9.81x/43

(w/l)=0.23x N/cm

From equation contition: (F_{J} +F_{T} =9.81x n)

F_{T} (510)=9.81x  (210+21.5)

F_{T} (510)=9.81 x (231.5)

F_{T} =4.452x N.

F_{J} =9.81x-4.452x

F_{J} =5.358 xN

Therefore F_{J} \geq F_{T}

To learn more about mass per unit length, refer to:

brainly.com/question/24180692

#SPJ9

4 0
2 years ago
A golf ball is hit with a golf club. While the ball flies through the air, which forces act on the ball? Neglect air resistance.
34kurt

To solve this problem it is necessary to apply the equation related to the Gravitational Force, the equation describes that

F = \frac{GMm}{r^2}

Where,

G = Gravitational Universal Constant

M = Mass of Earth (or Bigger star)

m = Mass of Object  (or smallest star)

r = Radius

From the statement we know that once the impact is made, the golf ball is subjected to the forces that are exerted in nature. Since the air resistance, which would represent the drag force, is ignored. Only the forces related to gravity remain.

The gravitational force carries 'pushes' or 'attracts' the body towards the earth, while the speed decreases as it reaches its maximum height.

When the ball has reached its maximum height only the force of gravity begins to act on it, generating the attraction to the earth in parabolic motion.

Therefore the correct answer is B.

6 0
4 years ago
Read 2 more answers
The nuclear potential that binds protons and neutrons in the nucleus of an atom is often approximated by a square well. Imagine
slega [8]

3. The nuclear potential that binds protons and neutrons in the nucleus of an atom

is often approximated by a square well. Imagine a proton confined in an infinite

square well of length 10−5 nm, a typical nuclear diameter. Calculate the wavelength

and energy associated with the photon that is emitted when the proton undergoes a

transition from the first excited state (n = 2) to the ground state (n = 1). In what

region of the electromagnetic spectrum does this wavelength belong?

Answer 3

We are given that,

Length of square well = L = 10−5

nm = 10−14 m.

Energy of proton in state n is given by,

En =

π

2n

2~

2

2mpL2

,

where L is the width of the square well.

⇒ E1 =

π

2~

2

2mpL2

E2 =

4π

2~

2

2mpL2

·

5 0
3 years ago
I was driving 150 km/hr for 20 km, then had to pull over for a quarter of an hour to replace my tire, and then drove the last 3.
Likurg_2 [28]

Answer:

ertyu

Explanation:

4 0
3 years ago
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