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Svetradugi [14.3K]
3 years ago
5

Engineers are designing a curved section of a highway. If the radius of curvature of the curve is 173 m, at what angle should th

e curve be banked so that a car traveling at 29.0 m/s will stay on the road without the aid of frictional forces?

Physics
1 answer:
egoroff_w [7]3 years ago
8 0

Answer: The angle Ø = 26

Explanation:

The weight and the normal force of the road are the only two external forces acting on the car. A frictionless surface can only exert a force that is perpendicular to the surface. This is a normal force.

Since the car does not leave the surface of the road, the vertical components of the two external forces must be equal in magnitude and opposite in direction. Whereas ;

Horizontal component = centripetal force. While

The vertical component = Mg

Revolving the two components gives: tanØ = V^2/rg

Please find the attached file for the solution

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A device that uses electromagnetic induction to transfer electrical energy from one circuit to another is a(n)_____.
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A device that uses electromagnetic induction to transfer electrical energy from one circuit to another is a transformer.

<h3>Which device uses electromagnetic induction to transfer electrical energy from one circuit to another?</h3>

  • A transformer is an electrical device that transfers energy from one electric circuit to another using the electromagnetic induction principle.
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2 years ago
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The correct answer is The stages happens in the cytoplasm.

Explanation:

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Answer: The given statement is True.    

The proliferation of photosynthetic planktons results in harmful algal blooms. Due to this, the surface of the water body gets completely covered with algal bloom. This blocks the sunlight as it can not penetrate the water. Due to this, photosynthetic planktons are no more able to perform photosynthesis. This ultimately ends up depleting all oxygen from the body of water.  

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Answer:

45°

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I = Polarized light after 3 filter = 0.5 W/m²

I_0 = Initial light intensity = 4 W/m²

The intensity of polarized light is given by

I=I_0cos^2Acos^245cos^245\\\Rightarrow A=cos^{-1}\sqrt{\dfrac{I}{I_0cos^245cos^245}}\\\Rightarrow A=cos^{-1}\sqrt{\dfrac{0.5}{4\times cos^245\times cos^245}}\\\Rightarrow A=45^{\circ}

Hence, the angle relative to the vertical was the light initially polarized is 45°

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3 years ago
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