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hjlf
3 years ago
10

According to Newton's third law of motion, for every action force, there is

Chemistry
1 answer:
Nonamiya [84]3 years ago
7 0

Answer:

A. an equal and opposite reaction force

Explanation:

This means that there is a natural reaction of force

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What element has the electron configuration below? *<br><br> please help me
timofeeve [1]

Answer:

Symbol Ar

Group 18

Electron configuration- 1s² 2s² 3p6 3s² 3p6

Explanation:

The 6 is small and will be placed in top but I don't have the option that's why I wrote like that

8 0
2 years ago
Why are zeppelin filled with hydrogen a bad idea?
8_murik_8 [283]

the fire that destroyed due to the extremely flammable aluminium /iron oxide  based  applied to the outer skin of the craft. This was struck by lightning and caught fire well before the hydrogen ignited.

Explanation:

7 0
3 years ago
Paul went to his friend's 2 km from his house, he used his bike and took him 9 minutes.
damaskus [11]

The average speed : 3.07 m/s

<h3>Further explanation</h3>

Given

d1 = 2 km

t1 = 9 min

d2 = 1.5 km

t2 = 10 min

Required

The average speed

Solution

Average speed = total distance : total time

total distance :

= d1+d2

= 2+1.5

=3.5 km

total time :

= t1+t2

= 9 min + 10 min

= 19 min

Average speed :

= 3.5 km : 19 min

= 0.184 km/min

= 3.07 m/s

8 0
3 years ago
I need help on this it’s due today!!!
stich3 [128]
Atmosphere. You can think of the atmosphere as the outer shell for earth.
6 0
2 years ago
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Determine the mass of Al(C2H3O2)3 that contains 2.63 Χ 1024 atoms of oxygen.
sergejj [24]

The molecular formula of compound is Al(C_{2}H_{3}O_{2})_{3}.

Since, in 1 mole of  Al(C_{2}H_{3}O_{2})_{3} there are 6.023\times 10^{23} atoms of  Al(C_{2}H_{3}O_{2})_{3}.

Thus, according to molecular formula, in 1 mole of  Al(C_{2}H_{3}O_{2})_{3} there are 6\times 6.023\times 10^{23}=3.61\times 10^{24} atoms of oxygen atoms.

1 atom of oxygen will be present in \frac{1}{3.61\times 10^{24}} moles of Al(C_{2}H_{3}O_{2})_{3} . Thus,

2.63\times 10^{24} atoms of oxygen \rightarrow \frac{2.63\times 10^{23}}{3.61\times 10^{24}}= 0.7285 moles of Al(C_{2}H_{3}O_{2})_{3}.

Molar mass of Al(C_{2}H_{3}O_{2})_{3} is 236 g/mol, mass can be calculated as follows:

m=n\times M=0.7285 mol\times 236 g/mol=172 g

Therefore, mass of Al(C_{2}H_{3}O_{2})_{3} will be 172 g.

5 0
3 years ago
Read 2 more answers
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