Answer:
Answer for the given statements: (1) T , (2) F , (3) T , (4) F , (5) F
Explanation:
At the given interval, concentration of HI = 
Concentration of 
= 
Concentration of 
= 
Reaction quotient,
, for this reaction = ![\frac{[H_{2}][I_{2}]}{[HI]^{2}}](https://tex.z-dn.net/?f=%5Cfrac%7B%5BH_%7B2%7D%5D%5BI_%7B2%7D%5D%7D%7B%5BHI%5D%5E%7B2%7D%7D)
species inside third bracket represents concentrations at the given interval.
So, 
So, the reaction is not at equilibrium.
As 
therefore reaction must run in reverse direction to reduce and make it equal to 
. That means HI(g) must be produced and must be consumed.
The first dissociation for H2X:
H2X +H2O ↔ HX + H3O
initial 0.15 0 0
change -X +X +X
at equlibrium 0.15-X X X
because Ka1 is small we can assume neglect x in H2X concentration
Ka1 = [HX][H3O]/[H2X]
4.5x10^-6 =( X )(X) / (0.15)
X = √(4.5x10^-6*0.15)
∴X = 8.2 x 10-4 m
∴[HX] & [H3O] = 8.2x10^-4
the second dissociation of H2X
HX + H2O↔ X^2 + H3O
8.2x10^-4 Y 8.2x10^-4
Ka2 for Hx = 1.2x10^-11
Ka2 = [X2][H3O]/[HX]
1.2x10^-11= y (8.2x10^-4)*(8.2x10^-4)
∴y = 1.78x10^-5
∴[X^2] = 1.78x10^-5 m
Explanation:
elctronic configuration of manganese
Mn=1s²2s²2p⁶3s²3p⁶4s²3d⁵
ground state
Mn=Ar3d⁵4s²
note that Ar is argon
Answer:
Its b its the state not anything else
Answer:
Element with 6s subshell
Explanation:
Reactivity of an element depends on the electronic configuration and position of element in the periodic table as reactivity increases as we go down the periodic table.
This is so because number of shell increases as move down the periodic table and the last electron is further away from the nucleus.
Element with 6s subshell is the largest among 3s and 4s subshell and has more number of shells so it will react more than 3s and 4s subshell.
Hence, the correct answer is "Element with 6s subshell".
