Speific heat capacity is measured with the aid of determining how a whole lot warmth electricity is needed to increase one gram of a substance one digree Celsius. The Speific heat capacity of water is 4.2 joules per gram per degree Celsius or 1 calorie in step with gram per digree Celsius.
The specific heat capacity is defined as the amount of heat (J) absorbed consistent with unit mass (kg) of the substance while its temperature increases 1 ok (or 1 °C), and its units are J/(kg k) or J/(kg °C).
Factors specific heat capacity relate to are temperature and strength.
The Speific heat capacity C can be measured as q = mC∆T
Or, C = q/m∆T
where,
C is the specific heat capacity
q is the quantity of heat required
m is the mass
∆T is the change in temperature
As a consequence so as to degree the specific heat capacity we need to recognize mass of the substance, quantity of heat lost or gain by the substance and the exchange in temperature.
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1) Use the fact that 1 mol of gas at STP occupies 22.4 liter
=> 1 mol / 22.4 l = x / 0.125 l => x = 0.125 l * 1 mol / 22.4 l = 0.00558 mol
2) Now use the molar mass of the gas
molar mass of CO2 ≈ 44 g / mol
Formula: molar mass = mass in grams / number of moles =>
mass in grams = molar mass * number of moles = 44 g/mol * 0.00558 moles
mass = 0.246 g
Answer: 0.246 g
Answer:
c.- How much of the reactants are needed and how much product will made.
Explanation:
The moles is the matter unit used in chemistry to simplify some calculations, instead of using grams. Also the moles are very useful because the chemical reaction can be balanced.
When a Chemical reaction is balanced, then it can be easily to calculate how many moles are necessary to add in a process to obtain a quantity of grams of a product.
The CH4 molecule has the lowest molecular weight, so it has the lowest boiling point.
Hope I helped :)
Answer: Volume of the gas at STP is 22.53 L.
Explanation:
Given : Volume = 125 mL (as 1 mL = 0.001 L) = 0.125 L
Temperature = 
Pressure = 
According to the ideal gas equation, the volume of given nitrogen gas is calculated as follows.
PV = nRT
where,
P = pressure
V = volume
n = number of moles
R = gas constant = 0.0821 L atm/mol K
T = temperature
Substitute the values into above formula as follows.
Hence, volume of the gas at STP is 22.53 L.
