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SVEN [57.7K]
3 years ago
15

Whats the formula for selenium pentaoxide, iodine trichloride, zinc (1) nitride, chromium (III) bicarbonate, and there molar mas

s
Answer one of them plz and thx
Chemistry
1 answer:
Phoenix [80]3 years ago
3 0

Answer:

1) Se2O5

2) I2O6

3)Zn3n2

4) Cr(HCO3)3

Explanation:

selenium pentaoxide (= also called diselenium pentoxide)

= Se2O5

⇒ Se = 78.97 g/mol

⇒ O = 16 g/mol

⇒ 2*78.97 + 5*16 = 237.94 g/mol

iodine trichloride

= I2O6

⇒ I = 126.9 g/mol

⇒ Cl = 35.45 g/mol

⇒ 2* 126.9 + 6 * 35.45 = 466.5 g/mol

zinc (1) nitride does not exist  (it's Zinc(ii)nitride

The oxidation number for zinc is always 2

Zn3n2

⇒ Zn = 65.38 g/mol

⇒ N = 14 g/mol

⇒3*65.38 + 2* 14 = 224.14 g/mol

chromium (III) bicarbonate

Cr(HCO3)3

⇒ Cr = 52 g/mol

⇒ H = 1.01 g/mol

⇒ C = 12 g/mol

⇒ O = 16 g/mol

52 + 3*1.01 + 3*12 + 6*16 = 235.03 g/mol

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