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stellarik [79]
3 years ago
9

Solve the following compound inequality. 5x+7 is less than or equal to -3 or 3x-4 is greater than or equal to 11

Mathematics
1 answer:
suter [353]3 years ago
3 0

Answer:

the answer is A

Step-by-step explanation:

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Does x+y=1 have an x-intercept of (1,0) and y intercept of (0,1)?
aivan3 [116]

Answer:

Yes

Step-by-step explanation:

To find the y intercept of this formula, you first need to convert it into slope intercept form.

x+y=1

y=-x+1

Here, the slope is negative 1 and the y intercept is (0,1). If you imagine the line with a slope of negative 1, it will indeed cross the x axis at (1,0). Hope this helps!

4 0
3 years ago
Given the function f(x)=x^4+8x^3+16x^2, determine all intervals on which f is decreasing.
ValentinkaMS [17]

Answer:

see attachment

Step-by-step explanation:

4 0
3 years ago
You work at a grocery store. Last week, you sold 213 potatoes to customers and lost 6 potatoes due to expiration. The store paid
oksian1 [2.3K]

Answer:

Total Sold potatoes =213

Paid price=213*0.47=100.11

Sold price=213*0.88=187.44

Lost potatoes=2.82

=187.44-100.11-2.82

Profit =84.51

5 0
3 years ago
How do you simplify this expression step by step using trigonometric identities?
olga55 [171]

\bf \textit{Pythagorean Identities}\\\\ 1+tan^2(\theta)=sec^2(\theta) \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ sec^2(\theta )cos^2(\theta )+tan^2(\theta )\implies \cfrac{1}{\begin{matrix} cos^2(\theta ) \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix} }\cdot \begin{matrix} cos^2(\theta ) \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix} +tan^2(\theta ) \\\\\\ 1+tan^2(\theta )\implies sec^2(\theta )

5 0
3 years ago
Will ran the diagonal distance across a square field measuring 40 yards on each side. James Ran the diagonal distance across A r
ozzi

Answer:

<u>Will</u> ran the longer distance.

He run <u>56.40 yards</u> longer distance.

Step-by-step explanation:

<u><em>The question is incorrect so the correct question is below.</em></u>

Will ran the diagonal distance across a square field measuring 40 yards on each side. James ran the distance across a rectangular field with a length of 25 yards and a width of 35 yards. Who ran a longer distance,and how much longer did he run?

Now, to find the person who ran longer distance and the distance he run.

Will ran the diagonal distance across a square field.

The length of square field = 40 yards.

So, we put formula to get the diagonal of square:

Diagonal=length\sqrt{2}

Diagonal=40\times \sqrt{2}

Diagonal=40\times 1.41

Diagonal=56.40\ yards.

Thus, Will ran 56.40 yards diagonal distance of the square field.

Now, James ran the distance across a rectangular field with a length of 25 yards and a width of 35 yards.

So, to get the diagonal of rectangular field we use pythagorean theorem:

Diagonal^2=length^2+width^2

Diagonal^2=25^2+35^2

Diagonal^2=625+1225

Diagonal^2=1850

<em>Using square root on both sides we get:</em>

Diagonal=43.01\ yards.

Hence, James ran the diagonal distance 43.01 yards across the rectangular field.

<em>Now, we see the diagonal distance of both Will and James.</em>

<em>As, Will ran 56.40 yards and James ran 43.01 yards.</em>

<em>So, Will ran longer distance than James. And he run 56.40 yards</em>.

Therefore, Will ran the longer distance.

He run 56.40 yards longer distance.

4 0
3 years ago
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