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Salsk061 [2.6K]
3 years ago
10

Density is calculated by dividing the ________ by the _________.

Physics
2 answers:
Katen [24]3 years ago
8 0
Mass of the object by its volume
Nuetrik [128]3 years ago
7 0
Dividing the mass of an object by its volume.?
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The __________ pedal in a stick shift vehicle enables a driver to shift gears.
mamaluj [8]
The answer is C. Clutch
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It is night. Someone who is 4 feet tall is walking away from a street light at a rate of 8 feet per second. The street light is
KiRa [710]

Answer: 4 ft/s

Explanation:

Given

height of man=4 ft

speed of person v=8 ft/s

height if street light=12 ft

Let x be the distance between person and street light and y be the length of his shadow

From diagram

as the two triangle ADE and ABC are similar therefore we can say that

\frac{4}{12}=\frac{y}{x+y}

\frac{1}{3}=\frac{y}{x+y}

x+y=3y

x=2y

differentiate above Equation w.r.t time we get

\frac{\mathrm{d} x}{\mathrm{d} t}=2\frac{\mathrm{d} y}{\mathrm{d} t}

\frac{\mathrm{d} y}{\mathrm{d} t}=\frac{8}{2}=4 ft/s

6 0
3 years ago
A test of the prototype of a new automobile shows that the minimum distance for a controlled stop from 95 km/h to zero is 55 m.
iris [78.8K]

Answer:

-0.64525g

Explanation:

t = Time taken for the car to stop

u = Initial velocity = 95 km/h

v = Final velocity = 0 km/h

s = Displacement

a = Acceleration

Equation of motion

v^2-u^2=2as\\\Rightarrow a=\frac{v^2-u^2}{2s}\\\Rightarrow a=\frac{0^2-95^2}{2\times 0.055}\\\Rightarrow a=-82045.45\ km/h^2

Converting to m/s²

a=82045.45=\frac{82045.45\times 1000}{3600\times 3600}=-6.33\ m/s^2

g = Acceleration due to gravity = 9.81 m/s²

Dividing both the accelerations, we get

\frac{a}{g}=\frac{-6.33}{9.81}=-0.64525\\\Rightarrow a=-0.64525g

Hence, acceleration of the car is -0.64525g

8 0
4 years ago
About how many days in the moon’s cycle is it waxing?.
Monica [59]

Answer: 29.5 days

The waxing moon phase comprises three separate moon phases: the Waxing Crescent, First Quarter, and the Waxing Gibbous.

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2 years ago
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what would the net force be on the box in the problems shown below.( both force and direction).​ for all four diagrams. please e
DIA [1.3K]

Answer:
A) object moves 20 N [West] or -20 N [East]
B) object moves 6 N [South] or -6 N [North]
C) object moves 90 N [West] or -90 N [East]
D) object does not move and is at rest*

*Rest means 0


Why:

A)both forces from north and south that are pushing against the object neutralize each other. Assume that north is positive and south is negative: 20 [N] + (-20) [S] = 0
On West and east, you can see that west has a greater force. Assume that west is negative and east is positive: 50 [E] + (-70) [W] = -20 [E]
8 0
3 years ago
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