Answer:
A) 2
Explanation:
Given;
magnetic field of the coil, B = 1.6 T
frequency of the coil, f = 75 Hz
maximum emf developed in the coil, E = 56.9 V
area of the coil, A = 0.15 m x 0.25 m = 0.0375 m²
The maximum emf in the coil is given by;
E = NBAω
Where;
N is the number of turns
ω is the angular velocity = 2πf = 2 x 3.142 x 75 = 471.3 rad/s
N = E / BAω
N = 56.9 / (1.6 x 0.0375 x 471.3)
N = 2 turns
Therefore, the value of N is 2
A) 2
Answer:
can someone tell me the answer plz I'm in a rush
The correct answer is: Option (3) 9.8 N/kg
Explanation:
According to Newton's Law of Gravitation:
--- (1)
Where G = Gravitational constant = 6.67408 × 10⁻¹¹ m³ kg⁻¹ s⁻²
m = Mass of the body = 2 kg
M = Mass of the Earth = 5.972 × 10²⁴ kg
R = Distance of the object from the center of the Earth = Radius of the Earth + Object's distance from the surface of the Earth = (6371 * 10³) + 3.0 = 6371003 m
Plug in the values in (1):
(1)=>
Now that we have force strength at the location, we can use:
Force = mass * gravitational-field-strength
Plug in the values:
19.63 = 2.0 * gravitational-field-strength
gravitational-field-strength = 19.63/2 = 9.82 N/kg
Hence the correct answer is Option (3) 9.8 N/kg
Answer:
A. Force on parent is greater than the force on child
B. The net force acting on the bodies is zero for each.
C. the drag force on the parent is greater than the drag force on the child.
Explanation:
The child and the parent jump together form a certain height where the mass of the parent is greater than the mass of the child.
A
Before opening the parachute the drag force is negligible and so their velocity and acceleration are same simultaneously. The total force acting on the child is lesser than the total force of gravity on the child because the force of gravity is given as:
where:
m= mass
g= acceleration due to gravity
So when the mass is greater then the force of gravity is also greater on the body.
B
During the uniform velocity motion there is no acceleration in the body and hence we can say the there is no net force acting on the body.
The net force acting on the body is zero.
C
The force of drag acts due to parachute on each of the body when falling with uniform motion, this drag force is equal to the force of gravity acting on each of them individually.
So the drag force on the heavier body is greater than the drag force on the lighter body. During this condition the bodies fall with a uniform velocity called terminal velocity.
where:
density of the air
A= area normal to the direction of fall
v= terminal velocity
coefficient of drag