Question

A scuba diver, submerged under water looks up and seessunlight

Answer 1

Answer:

$41.7975\ ^{\circ}$

Explanation:

$n_2$ = Refraction index of water = 1.333

$n_1$ = Refraction index of air = 1

$\theta_2$ = Angle of sunlight = 30°

From Snell's law we have

$\dfrac{n_1}{n_2}=\dfrac{sin\theta_2}{sin\theta_1}\\\Rightarrow \theta_1=sin^{-1}\dfrac{n_2sin\theta_2}{n_1}\\\Rightarrow \theta_1=sin^{-1}\dfrac{1.333sin30}{1}\\\Rightarrow \theta_1=41.7975\ ^{\circ}$

The angle measured from the vertical does the sunlight strike thesurface of the water is $41.7975\ ^{\circ}$