What is the frequency of a wave that has a wavelength of 3m that is traveling at a speed of 9m/s

A 1600 kg helicopter has 250,000 J of gravitational energy. What is its

aleksandrvk [35]

Answer:

15.9 m

Explanation:

Use the equation for gravitational potential energy (Ug):

Ug= mass*g*height

250,000 J= 1600 kg*9.8 m/s^2*height

height= 15.9 m

Hope this helps!!! :)

6 0

3 years ago

Three very small spheres of mass 2.50 kg, 5.00 kg, and 8.00 kg are located on a straight line in space away from everything else

Aliun [14]

Answer:

The net gravitational force it exerts is $F_{net}=9.66*10^{-8}N$

Explanation:

Newton's Law of Gravitation can be written as

$F=\frac{Gm_{1}m_{2}}{r^{2} }$

where G is the Gravitational Constant, m1 and m2 are the masses of two objects, and r is the distance between them. In this case, the spheres are loacted in straight line, so instead of a vector r, we have a distance x in meters. The distances and masses are given in the problem, and the smaller sphere is between the other two spheres. This means the sphere 1 is in the middle, the sphere 2 is on the left of 1, and the sphere 3 is on the right of 1, so

$F_{21} =\frac{Gm_{1}m_{2}}{x_{21}^{2} }$ is the force that 2 feels because of 1, and

$F_{31} =\frac{Gm_{1}m_{3}}{x_{31}^{2} }$ is the force that 3 feels because of 1.

If we replace the data in those previous equations, we have that

$F_{21} =\frac{G(2.5)(5) }{(0.08)^{2} }=1.3*10^{-7}N$

$F_{31} =\frac{G(2.5)(8) }{(0.2)^{2} }=-3.34*10^{-8}N$

Finally, adding both results, the net force the sphere 1 exerts is

$F_{net}=9.66*10^{-8}N$

6 0

3 years ago

A hockey puck with a mass of 0.159 kg slides over the ice. The puck initially slides with a speed of 4.75 m/s, but it comes to a

Anton [14]

Answer:

The energy dissipated as the puck slides over the rough patch is 1.355 J

Explanation:

Given;

mass of the hockey puck, m = 0.159 kg

initial speed of the puck, u = 4.75 m/s

final speed of the puck, v = 2.35 m/s

The energy dissipated as the puck slides over the rough patch is given by;

ΔE = ¹/₂m(v² - u²)

ΔE = ¹/₂ x 0.159 (2.35² - 4.75²)

ΔE = -1.355 J

the lost energy is 1.355 J

Therefore, the energy dissipated as the puck slides over the rough patch is 1.355 J

5 0

3 years ago

Surrounding a magnet is a magnetic field. Surrounding an electron is an electric field. Surrounding Earth is

trasher [3.6K]

Answer: B. A gravitational field

Explanation:

Surrounding earth is gravitational field. Gravitational field is a region of space were gravitational force can be felt and gravitational force is the gravitational pull on the surface of the earth. The presence of this gravity is what allow us to be able to walk freely without falling. It also make us jump up and be able to land back on the ground. Assuming there are no force of gravity in the surface of the earth, there won't be any possibility of landing back on the ground after jumping.

6 0

3 years ago

Unpolarized light passes through a vertical polarizing filter, emerging with an intensity I0. The light then passes through a ho

antiseptic1488 [7]

To solve this problem it is necessary to apply the concepts related to Malus' law. Malus' law indicates that the intensity of a linearly polarized ray of light that passes through a perfect analyzer with a vertical optical axis is equivalent to:

$I = I_0 cos^2(\theta)$