Help!! I have no idea how to do this. :(

Please answer these questions asap please!!! Thank you!

Len [333]

Answer:

a= 1%

b= 0.1%

c= 0.1875% probably have to round

Step-by-step explanation:

a= 2/2= 1

B= 1/10=0.1

c= 1.5/8= 0.1875

6 0

2 years ago

Litter such as leaves falls to the forest floor, where the action of insects and bacteria initiates the decay process. Let A be

Travka [436]

Answer:

D = L/k

Step-by-step explanation:

Since A represents the amount of litter present in grams per square meter as a function of time in years, the net rate of litter present is

dA/dt = in flow - out flow

Since litter falls at a constant rate of L grams per square meter per year, in flow = L

Since litter decays at a constant proportional rate of k per year, the total amount of litter decay per square meter per year is A × k = Ak = out flow

So,

dA/dt = in flow - out flow

dA/dt = L - Ak

Separating the variables, we have

dA/(L - Ak) = dt

Integrating, we have

∫-kdA/-k(L - Ak) = ∫dt

1/k∫-kdA/(L - Ak) = ∫dt

1/k㏑(L - Ak) = t + C

㏑(L - Ak) = kt + kC

㏑(L - Ak) = kt + C' (C' = kC)

taking exponents of both sides, we have

$L - Ak = e^{kt + C'} \\L - Ak = e^{kt}e^{C'}\\L - Ak = C"e^{kt} (C" = e^{C'} )\\Ak = L - C"e^{kt}\\A = \frac{L}{k} - \frac{C"}{k} e^{kt}$

When t = 0, A(0) = 0 (since the forest floor is initially clear)

$A = \frac{L}{k} - \frac{C"}{k} e^{kt}\\0 = \frac{L}{k} - \frac{C"}{k} e^{k0}\\0 = \frac{L}{k} - \frac{C"}{k} e^{0}\\\frac{L}{k} = \frac{C"}{k} \\C" = L$

$A = \frac{L}{k} - \frac{L}{k} e^{kt}$

So, D = R - A =

$D = \frac{L}{k} - \frac{L}{k} - \frac{L}{k} e^{kt}\\D = \frac{L}{k} e^{kt}$

when t = 0(at initial time), the initial value of D =

$D = \frac{L}{k} e^{kt}\\D = \frac{L}{k} e^{k0}\\D = \frac{L}{k} e^{0}\\D = \frac{L}{k}$

4 0

2 years ago

Simplify 1/3 + 1/5 - 1/7 divided by 1/x

fgiga [73]

41x
—— = the answer.
105

4 0

3 years ago

Can someone explain how to answer this

olya-2409 [2.1K]

Answer:

q= -ck+dp/

-k+d

Step-by-step explanation:

Step 1:

Multiply both sides by p.

dp=ck−kq+pq

Step 2:

Flip the equation.

ck−kq+pq=dp

Step 3:

Add -ck to both sides.

−kq+pq=−ck+dp

Step 4:

Factor out variable q.

q(−k+p)=−ck+dp

Step 5:

Divide both sides by -k+p.

q= -ck+dp/

-k+d

Sorry if it's all letters and u needed numbers.

7 0

2 years ago

during a class election tge ratio of students who voted for candidate A compared to candidate B was 10:7. if candidate A receive

telo118 [61]

85 votes total for both candidates

4 0

3 years ago