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harina [27]
2 years ago
9

How many moles are in 395 grams of KMnO4 if the molar mass is 158 g/mole? please help me

Chemistry
1 answer:
Gala2k [10]2 years ago
8 0

Answer:

I have no idea

Explanation:

I don’t know

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A compressed gas cylinder is filled with 5270 g of argon gas. The pressure inside the cylinder is 2050 psi at a temperature of 1
LuckyWell [14K]

Answer:

A compressed gas cylinder is filled with 5270 g of argon gas.

The pressure inside the cylinder is 2050 psi at a temperature of 18C.

The valve to the cylinder is opened and gas escapes until the pressure inside the cylinder is 650. psi and the temperature are 26 C.

How many grams of argon remains in the cylinder?

Explanation:

First, calculate the volume of argon gas that is present in the gas cylinder by using the ideal gas equation:

Mass of Ar gas is --- 5270g.

The number of moles of Ar gas:

Number of moles of Ar gas=\frac{given mass of Ar}{its atomic mass} \\                                             =\frac{5270g}{39.948g/mol} \\                                             =131.9mol

Temperature T=(18+273)K=291K

Pressure P=2050psi

2050* 0.0680atm\\\\=139.4atm\\

Volume V=?

PV=nRT\\139.4atm * V=131.9mol *0.0821L.atm.mol-1.K-1 * 291K\\=>V=\frac{131.9mol *0.0821L.atm.mol-1.K-1 * 291K}{139.4atm} \\=>V=22.6L

Using this volume V=22.6L

Pressure=650psi=44.2atm

Temperature T= (26+273)K=299K

calculate number of moles "n" value:

PV=nRT\\=>n=\frac{PV}{RT} \\=>n=\frac{44.2atm*22.6L}{0.0821L.atm.mol^-1K^-1* 299K} \\=>n=40.7mol

Mass of 40.7mol of Ar gas:

mass of Ar gas=number of moles * its atomic mass\\\\                        =40.7mol* 39.948g/mol\\\\                        =1625.8g

Answer:

The mass of Ar gas becomes 1625.8g.

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Answer:

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Therefore our answer must be Option B

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there about 5000 elements, which combine to form the vast number of diffrent substances in the world around us
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