Cyclic compound A has molecular formula C5H10 and undergoes monochlorination to yield exactly three different constitutional iso
mers. Identify compound A and show the monochlorination products.
1 answer:
Answer:
A: 1,2-dimethylcyclopropane
Explanation:
The possible cyclic structure with formula C₅H₁₀ are shown in the image.
A is a cyclic compound. On monochlorination, A yields 3 products.
To have 3 products on monochlorination, there should be three different carbon atoms.
Considering structure 1, all carbons have same nature, thus only one product will be formed and thus not a structure of A.
Considering structure 2, there are two different carbon atoms, thus two different structure are formed and thus not a structure of A.
Considering structures 3 and 4 , there are four different carbon atoms, thus four products will be formed and either of them are not a structure of A.
Considering structure 5, there are three different carbon atoms, thus three different structure are formed and thus the A is structure 5.
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Answer:
a. Approximately .
b. Approximately .
Explanation:
The unit of concentration "" is equivalent to "
", which means "moles per liter."
However, the volume of both solutions were given in mililiters . Convert these volumes to liters:
.
.
In a solution of volume where the concentration of a solute is
, there would be
(moles of) formula units of this solute.
Calculate the number of moles of formula units in each of the two solutions:
Solution in a.:
.
Solution in b.:
.
What volume of that (same as
)
solution would contain that many
For the solution in a.:
.
Convert the unit of that volume to milliliters:
.
Similarly, for the solution in b.:
.
Convert the unit of that volume to milliliters:
.