Answer:
Yes, Pb3(PO4)2.
Explanation:
Hello there!
In this case, according to the given balanced chemical reaction, it is possible to use the attached solubility series, it is possible to see that NaNO3 is soluble for the Na^+ and NO3^- ions intercept but insoluble for the Pb^3+ and PO4^2- when intercepting these two. In such a way, we infer that such reaction forms a precipitate of Pb3(PO4)2, lead (II) phosphate.
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Answer:
Answer: 3.01 * 10^35
Explanation:
500,000,000,000 * 6.02 * 10^23
Answer:
The van't Hoff factor = 3.20
Explanation:
Step 1: data given
Osmotic pressure of a 0.050 M Solution is 3.85 atm
Temperature = 20.0 °C
Step 2:
Osmotic pressure depends on the molar concentration of the solute but not on its identity.
We can calculate the osmotic pressure by:
π = i.M.R.T
⇒ with π = osmotic pressure = 3.85 atm
⇒ with i = van 't Hoff factor = TO BE DETERMINED
⇒ with M = molar concentration of the solution =0.050 M
⇒ with R = gas constant =0.08206 L * atm / mol* K)
⇒ with T = Temperature of the solution =20°C = 293 K
i = π / M.R.T
i = 3.85 / 0.050*0.08206*293
i = 3.20
The theoretical Van't Hoff factor is 4:
AlCl3(aq) → Al^3+(aq) + 3Cl^-(aq)
AlCl3 dissociates in 1 mol Al^3+ + 3 moles Cl-
Due to the interionic atractions the Van't hoff factor is less than the theoretical value of 4
Answer:
The answer is option b.
Explanation:
Amplitude is the distance apart each wave is.
