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3 years ago

0.000431 L Express your answer as an integer.

Chemistry

1 answer:

Molodets [167]3 years ago

3 0

A whole number, not a fraction, that can be negative, positive or zero are integers. They cannot have decimal places.

Now, converting 0.000431 L to decimal an integer as:

$0.000431 L = 431\times 10^{-6} L$

Since, $1 L = 10^{6} \mu L$

So, $431\times 10^{-6} L\times \frac{10^{6 \mu L}}{1 L} = 431 \mu L$ .

Hence, the integer value for 0.000431 L is $431 \mu L[$ .

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Answer:
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3 years ago

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Answer:

1) Ethanol

Explanation:

If we will have interactions we will need more energy to break them in order to go from liquid to gas. If we need more energy, therefore, the temperature will be higher.

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Then we have to analyze the hydrogen bonds formed in the other molecules. For ethanol, we will have only 1 hydrogen bond. For water and ethanoic acid, we will have 2 hydrogen bonds, therefore, we can discard the ethanol.

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2 years ago

A permanent magnet can affect:

ruslelena [56]

A. both permanent magnets and electromagnets.

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A permanent magnet can affect and attract any other permanent magnet and even electromagnet.

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3 years ago

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3 years ago

Thorium-234 has a half-life of 24.1 days. How many grams of a 150 g sample would you have after 120.5 days?

chubhunter [2.5K]

Answer:

8.625 grams of a 150 g sample of Thorium-234 would be left after 120.5 days

Explanation:

The nuclear half life represents the time taken for the initial amount of sample to reduce into half of its mass.

We have given that the half life of thorium-234 is 24.1 days. Then it takes 24.1 days for a Thorium-234 sample to reduced to half of its initial amount.

Initial amount of Thorium-234 available as per the question is 150 grams

So now we start with 150 grams of Thorium-234

$150 \times \frac{1}{2}=24.1$