1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
mr Goodwill [35]
3 years ago
15

Dinitrogen monoxide gas decomposes to form nitrogen gas and oxygen gas. How many grams of oxygen are formed when 10.0 g of dinit

rogen monoxide decomposes?
Chemistry
1 answer:
lina2011 [118]3 years ago
5 0

Answer:

There is formed 3.6352 grams of oxygen

Explanation:

<u>Step 1</u>: The balanced equation

2N2O(g)⇔2N2(g)+O2(g)

<u>Step 2</u>: Calculate moles of dinitrogen monoxide

Moles = mass/ Molar mass

Moles of N2O = 10 grams of N2O / 44.01 g/mole

Moles of N2O = 0.227 moles

<u>Step 3</u>: Calculate moles of oxygen

When 2 moles of N2O is consumed, there is produced 1 mole of O2 ( and 2 moles of N2)

That means for 0.2272 moles of N2O consumed, there is produced 0.1136 moles of O2

<u>Step 4:</u> Calculate mass of O2

mass of O2 = moles of O2 * Molar mass of O2

mass of O2 = 0.1136 moles * 32 g/moles

mass of O2 = 3.6352 grams

There is formed 3.6352 grams of oxygen

You might be interested in
The kinetic theory describes the _____ of particles in all matter
VladimirAG [237]
The kinetic theory describes the matter of particles in all matter
7 0
3 years ago
|
lilavasa [31]

1.66 M is the concentration of the chemist's working solution.

<h3>What is molarity?</h3>

Molarity (M) is the amount of a substance in a certain volume of solution. Molarity is defined as the moles of a solute per litres of a solution. Molarity is also known as the molar concentration of a solution.

In this case, we have a solution of Zn(NO₃)₂.

The chemist wants to prepare a dilute solution of this reactant.

The stock solution of the nitrate has a concentration of 4.93 M, and he wants to prepare 620 mL of a more dilute concentration of the same solution. He adds 210 mL of the stock and completes it with water until it reaches 620 mL.

We want to know the concentration of this diluted solution.

As we are working with the same solution, we can assume that the moles of the stock solution will be conserved in the diluted solution so:

n_1= n_2  (1)

and we also know that:

n = M x V_2

If we replace this expression in (1) we have:

M_1 x V_1= M_2 x V_2

Where 1, would be the stock solution and 2, the solution we want to prepare.

So, we already know the concentration and volume used of the stock solution and the desired volume of the diluted one, therefore, all we have to do is replace the given data in (2) and solve for the concentration which is M_2:

4.93 x 210 =  620 xM_2

M_2 = 1.66 M

This is the concentration of the solution prepared.

Learn more about molarity here:

brainly.com/question/19517011

#SPJ1

6 0
2 years ago
What hypothesis can you write about liquids
tekilochka [14]

Answer:

they are not solid

Explanation:

7 0
3 years ago
How many atoms of oxygen are in 1.00 mole of Cu(NO3)2 ?
vova2212 [387]

Answer:

1 mole of 02=6.022*10^23 02 molecules 1 02 molecules

Explanation:

SANA MAKATULONG PO ♥️♥️

3 0
3 years ago
What is the pH of 4.3x10^-7 M solution of H2CO3?
Rzqust [24]

Answer:

pH = -log[H⁺] = -log(4.75 x 10⁻⁷) = -(- 6.32 ) = 6.32

Explanation:

Given 4.3 x 10⁻⁷M H₂CO₃ (Ka1 = 4.2 x 10⁻⁷ &  Ka2 = 4.8 x 10⁻¹¹)

Note: The Ka2 value for the 2nd ionization step is so small (Ka2 = 4.8 x 10⁻¹¹) It will be assumed all of the hydronium ions (H⁺) come from the 1st ionization step.  

1st Ionization step

                    H₂CO₃        ⇄   H⁺ + HCO₃⁻

C(initial)     4.3 x 10⁻⁷             0         0

ΔC                   -x                  +x        +x

C(final)      4.3 x 10⁻⁷ - x         x          x

Note: the 'x' value in this analysis can not be dropped as the Conc/Ka value is less than 10². In this case he C/Ka ratio* (4.3E-7/4.2E-7 ≈ 1)  is far below 10².

So, one sets up the equilibrium equation to be quadric and the x-value can be determined.

Ka1 = [H⁺][HSO⁻]/[H₂SO₃] = (x)(x)/(4.3 x 10⁻ - x) = x²/(4.3 x 10⁻⁷ - x) = 4.2 x 10⁻⁷

=>   x² = 4.2 x 10⁻⁷(4.3 x 10⁻⁷ - x)

=>   x² + 4.2 x 10⁻⁷x - 1.8 x 10⁻¹³ = 0              

      a = 1, b = 4.2 x 10⁻⁷, c = - 1.8 x 10⁻¹³

x = b² ± SqrRt(b² - 4(1)(-1.8 x 10⁻¹³ / 2(1) =  4.75 x 10⁻⁷

x = [H⁺] = 4.75 x 10⁻⁷

pH = -log[H⁺] = -log(4.75 x 10⁻⁷) = -(- 6.4 ) = 6.4

______________________

* The Concentration/Ka-value is the simplification test for quadratic equations used in Equilibrium studies. If the C/Ka > 100 then one can simplify the C(final) by dropping the 'x' if used in this type analysis. However, if the C/Ka value is < 100 then the x-value must be retained and the solution is determined using the quadratic equation formula.

for ax² + bx + c = 0

x = b² ± SqrRt(b² - 4ac) / 2a

4 0
3 years ago
Other questions:
  • A plant grows toward a sunny window. This response is an example of A plant grows toward a sunny window. This response is an exa
    5·2 answers
  • The number of protons and neutrons in an atom is known as the
    13·2 answers
  • How many elements are represented in the formula CaCO3
    13·2 answers
  • A little boy has placed his pet squirrel into a balloon with a volume of 3L at a pressure of 1.0 atm. If the boy takes his pet s
    11·1 answer
  • What is the qualitative analysis of (nh4) 2co3 using NaOH, HCL, BaCL2, and AgNO3​
    13·1 answer
  • True or false. Sometimes de rodes end up on top of your ger rocks.​
    13·1 answer
  • How many grams of the parent isotope are left in the sample after three half lives?
    12·1 answer
  • 100 POINTS FOR QUESTION
    15·2 answers
  • A chemical equation calls for 2 water molecules. How many of each atom would be in this formula of 2H20?
    13·2 answers
  • How many moles of water form
    8·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!