Heat Transfer Lab
The following represents a lab set up for heat transfer. The cup on the left started with boiling water at 100 degrees C and the cup on the right has water at 20 degrees C. There is an aluminum bar between the two cups allowing heat to transfer from one cup into the other. The set up will be left alone for 20 minutes and temperatures of each cup of water will be recorded every minute for 20 minutes.
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PbCl2 would not dissolve because it is insoluble based on the solubility rules for substances that will dissolve in water. This compound would instead form a solid precipitate at the bottom of the container.
The given reaction is:
C4H10 + O2 → CO2 + H2O
The above equation is not balanced due to the unequal distribution of atoms on either side of equation
# atoms Reactants # atoms products
C = 4 C = 1
H = 10 H = 2
O = 2 O = 3
In order to balance it, multiply C4H10 by 2, O2 by 13, CO2 by 8 and H2O by 10 to get:
2C4H10 + 13 O2 → 8CO2 + 10H2O
