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Brilliant_brown [7]
2 years ago
5

What does the law of conservation of energy state? *

Physics
2 answers:
den301095 [7]2 years ago
8 0

Answer:

total energy before transfer is equal to total energy after transfer

Ann [662]2 years ago
7 0

Answer:

1 is the correct one Answer

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A mover loads a 100 kg box into the back of a moving truck by
NeX [460]

Answer:

2.7

Explanation:

The following data were obtained from the question:

Mass (m) of box = 100 Kg

Length (L) of ramp = 4 m

Height (H) of ramp = 1.5 m

Mechanical advantage (MA) of ramp =?

Mechanical advantage of a ramp is simply defined as the ratio of the length of the ramp to the height of the ramp. Mathematically, it is given by:

Mechanical Advantage = Lenght / height

MA= L/H

With the above formula, we can obtain the mechanical advantage of the ramp as follow:

Length (L) of ramp = 4 m

Height (H) of ramp = 1.5 m

Mechanical advantage (MA) of ramp =?

MA = 4/1.5

MA = 2.7

Therefore, the mechanical advantage of the ramp is 2.7

3 0
2 years ago
Students who embrace an innate mindset might view their poor performance in math as inevitable or beyond their control
PilotLPTM [1.2K]

Answer:

True

Explanation:

4 0
3 years ago
Read 2 more answers
If Judy walks 2 blocks north, 5 blocks west, and then 2 blocks south, what is her final
VladimirAG [237]

Answer: 2 blocks east if i'm not mistaken.

7 0
3 years ago
Determine the amount of potential energy of a 5.0Kg book that is moved to three different shelves on a bookcase. The height of e
rjkz [21]
Formula to find gravitational potential energy:
mgh
m: mass
g: gravitational acceleration
h: height (relative to reference level)

so the P.E. at 1.0.m is (5x9.8x1)= 49J
P.E. at 1.5m is (5x9.8x1.5) =73.5J
P.E. at 2.0m is (5x9.8x2)=98J
8 0
3 years ago
13. A step up transformer has 250 turns on its primary and 500 turns on it secondary. When the primary is connected to a 200 V a
Lisa [10]

Answer:

The output power is 2 kW

Explanation:

It is given that,

Number of turns in primary coil, N_p=250

Number of turns in secondary coil, N_s=500

Voltage of primary coil, V_p=200\ V

Current drawn from secondary coil, I_s=5\ A

We need to find the power output. It is equal to the product of voltage and current. Firstly, we will find the voltage of secondary coil as :

\dfrac{N_p}{N_s}=\dfrac{V_p}{V_s}

\dfrac{250}{500}=\dfrac{200}{V_s}

V_s=400\ V

So, the power output is :

P_s=V_s\times I_s

P_s=400\ V\times 5\ A

P_s=2000\ watts

or

P_s=2\ kW

So, the output power is 2 kW. Hence, this is the required solution.

8 0
3 years ago
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