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2 years ago

What does the law of conservation of energy state? *

Physics

2 answers:

den301095 [7]2 years ago

8 0

Answer:

total energy before transfer is equal to total energy after transfer

Ann [662]2 years ago

7 0

Answer:

1 is the correct one Answer

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A solid conducting sphere of radius 2.00 cm has a charge of 6.88 μC. A conducting spherical shell of inner radius 4.00 cm and ou

zepelin [54]

Explanation:

Given that,

Radius R= 2.00

Charge = 6.88 μC

Inner radius = 4.00 cm

Outer radius = 5.00 cm

Charge = -2.96 μC

We need to calculate the electric field

Using formula of electric field

$E=\dfrac{kq}{r^2}$

(a). For, r = 1.00 cm

Here, r<R

So, E = 0

The electric field does not exist inside the sphere.

(b). For, r = 3.00 cm

Here, r >R

The electric field is

$E=\dfrac{kq}{r^2}$

Put the value into the formula

$E=\dfrac{9\times10^{9}\times6.88\times10^{-6}}{(3.00\times10^{-2})^2}$

$E=6.88\times10^{7}\ N/C$

The electric field outside the solid conducting sphere and the direction is towards sphere.

(c). For, r = 4.50 cm

Here, r lies between R₁ and R₂.

So, E = 0

The electric field does not exist inside the conducting material

(d). For, r = 7.00 cm

The electric field is

$E=\dfrac{kq}{r^2}$

Put the value into the formula

$E=\dfrac{9\times10^{9}\times(-2.96\times10^{-6})}{(7.00\times10^{-2})^2}$

$E=5.43\times10^{6}\ N/C$

The electric field outside the solid conducting sphere and direction is away of solid sphere.

Hence, This is the required solution.

6 0

3 years ago

Select the correct answer. The motion of a car on a position-time graph is represented with a horizontal line. What does this in

enyata [817]

If the car's motion appears as a horizontal line on a position-time graph, it shows that as time changes, the car's position doesn't change.

This is just a complicated way to say that the car is not moving. (A)

7 0

2 years ago

A floating ice block is pushed through a displacement along a straight embankment by rushing water, which exerts a force on the

lions [1.4K]

The question is incomplete. Here is the complete question.

A floating ice block is pushed through a displacement vector d = (15m)i - (12m)j along a straight embankment by rushing water, which exerts a force vector F = (210N)i - (150N)j on the block. How much work does the force do on the block during displacement?

Answer: W = 4950J

Explanation: Work (W), in physics, is done when a force acts on an object that has a displacement form a place to another:

W = F · d

As the formula shows, Work is a scalar product, i.e, it results in a number, so, Work only has magnitude.

Force and displacement for the ice block are in 2 dimensions, then work will be:

W = (210)i - (150)j · (15)i - (12)j

W = (210*15) + (150*12)

W = 3150 + 1800

W = 4950J

During the displacement, the ice block has a work of 4950J

8 0

2 years ago