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2 years ago

What is a particulate?

Chemistry

2 answers:

nikklg [1K]2 years ago

7 0

Answer: A tiny solid suspended in the atmosphere

Explanation:

Gradpoint

FromTheMoon [43]2 years ago

5 0

Answer: The particulate is defined below.

Explanation:

Particulate is defined as the small solid or liquid particles which are suspended in gaseous medium.

Examples which define particulate the best are: Dust or soot particles which are evenly suspended in air or water and sulfuric acid droplets in air.

These particles contribute to air pollution to a major extent. The mixtures where dispersed medium is gas and dispersed phase are solid or liquid are known as aerosols.

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2.50 g of Zn is added to 5.00 g of HCl

Debora [2.8K]

Zn+2HCl ----> 2ZnCl2 + H2

For 2.50 g of Zn

Mass per mol = 2.50/molar mass of Zn = 2.50/65.38 = 0.0382 g/mol
There are two moles of ZnCl2 and total mass = 2*0.0382*molar mass of ZnCl2 = 2*0.0382*136.286 = 10.42 g

For 2 g of HCl

Mass per mol = 2/2*molar mass of HCl = 2/ (2*36.46) = 0.0274 g/mol
For the two moles of ZnCl2, mass produced = 2*0.0274*136.286 = 7.48 g

It can be noted that 2 g of HCl produced less amount of ZnCl and thus it is the limiting reagent.

5 0

2 years ago

Under identical conditions, separate samples of O2 and an unknown gas were allowed to effuse through identical membranes simulta

scoray [572]

Answer:

70.77 g/mol is the molar mass of the unknown gas.

Explanation:

Effusion is defined as rate of change of volume with respect to time.

Rate of Effusion= $\frac{Volume}{Time}$

Effusion rate of oxygen gas after time t = $E=\frac{4.64 mL}{t}$

Molar mass of oxygen gas = M = 32 g/mol

Effusion rate of unknown gas after time t = $E'=\frac{3.12 mL}{t}$

Molar mass of unknown gas = M'

The rate of diffusion of gas, we use Graham's Law.

This law states that the rate of effusion or diffusion of gas is inversely proportional to the square root of the molar mass of the gas. The equation given by this law follows:

$\text{Rate of effusion}\propto \frac{1}{\sqrt{\text{Molar mass of the gas}}}$

$\frac{E}{E'}=\sqrt{\frac{M'}{M}}$

$\frac{\frac{4.64 mL}{t}}{\frac{3.12 mL}{t}}=\sqrt{\frac{M'}{32 g/mol}}$

M' = 70.77 g/mol

70.77 g/mol is the molar mass of the unknown gas.

8 0

2 years ago

During oxidation of ethanol to ethanol, the ethanol formed was found to be contaminated with unconverted ethanol, describe how y

Dafna1 [17]

The process of how we would obtain ethanal free from ethanol is described in the explanations below.

In Chemistry, Ethanol undergoes oxidation in the presence of sodium dichromate plus sulphuric acid to yield ethanal and water.

The procedure for achieving this in the laboratory is as follows;

Step 1; Measure a quantity of a solution of sodium dichromate acidified in a dilute sulphuric acid and pour into a test tube.

Step 2; Add excess ethanol. This is because if we don't do so there will be plenty of oxidizing agent to carry out a second operation which changes the aldehyde to ethanoic acid. However, we need only the aldehyde.

Step 3; When the aldehyde ethanal begins to form which will be evident by the change in the colour of solution from orange to green, then the mixture should be distilled from the test tube and tbethe aldehyde collevted so that it doesn't undergo additional oxidation into ethanoic acid.

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4 0

2 years ago

Read 2 more answers

An atom has 6 protons and 9 neutrons in its nucleus. Calculate the mass number of the atom

pshichka [43]

Answer:

6+9=15

mass number =15

mass number = no. protons + no. of neutrons

5 0

2 years ago