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DerKrebs [107]
2 years ago
13

What is a particulate?

Chemistry
2 answers:
nikklg [1K]2 years ago
7 0

Answer: A tiny solid suspended in the atmosphere

Explanation:

Gradpoint

FromTheMoon [43]2 years ago
5 0

<u>Answer:</u> The particulate is defined below.

<u>Explanation:</u>

Particulate is defined as the small solid or liquid particles which are suspended in gaseous medium.

Examples which define particulate the best are: Dust or soot particles which are evenly suspended in air or water and sulfuric acid droplets in air.

These particles contribute to air pollution to a major extent. The mixtures where dispersed medium is gas and dispersed phase are solid or liquid are known as aerosols.

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A sample of helium gas inside a closed but flexible container occupies a volume of 355mL at 23°C. If the pressure is held consta
guapka [62]

Answer:

978.19° C

Explanation:

P1V1/T1 =P2V2/T2     Since the pressure is constant, this can be written as

V1/T1 = V2/T2      RE-ARRANGE TO

V2 *  T1/V1   = T2       Note:  T must be in Kelvin!!

1.5 L  *  (273.15 + 23)  / (.355 L ) = T2 = 1251.338 K  =978.19 C

6 0
1 year ago
What is the volume of the solution that would result by diluting 80.00 ml of 9.13×10−2 m naoh to a concentration of 1.60×10−2 m
aalyn [17]
The equation that we will use to solve this question is:
M1*V1 = M2*V2
where:
M1 is the initial concentration = 9.13*10^-2 M
V1 is the initial volume = 80 ml
M2 is the final concentration = 1.6*10^-2 M
V2 in the final volume that we need to find

Substitute with the values given in the equation to calculate the final volume as follows:
(9.13*10^-2*80) = (1.6*10^-2) * V2
V2 = 456.5 ml
7 0
3 years ago
Read 2 more answers
The Millikan oil-drop experiment, which was the first experiment to measure the charge of the electron, compared the electrical
Liono4ka [1.6K]

Answer:

True

Explanation:

The oil drop experiment was carried out by Robert Millikan and Harvey Fletcher in 1909 to determine the charge of an electron. By balancing downward gravitation force with upward drag and electric force, they suspended small charged droplets of oil between two metal electrodes.

The charge over an oil droplet was often an integral value of e, was determined by changing the intensity of the electric field.

So, the given statement is true

3 0
2 years ago
PLEASE HELP ME!!!!!!!!
Nostrana [21]

nswerllo

Explanation:

6 0
2 years ago
What’s chemical formula ammonium iodide?
Law Incorporation [45]

Answer:

NH4I

..................

I hope it helps

8 0
2 years ago
Read 2 more answers
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