Do covalent bonds dissolve in methanol

Acetaminophen (C8H9NO2) is the active ingredient in many nonprescription pain relievers. Each tablet contains 500 mg of acetamin

ohaa [14]

1) Molar mass C8H9NO2

Element Atomic mass    # of atoms mass
   g/mol g
C 12 8 12*8 = 96
H 1 9    1*9 = 9
N    14    1    14*1 = 14
O    16 2 16*2 = 32

      molar mass = 96 + 9 + 14 + 32 = 151 g/mol

2) Number of mols in a tablet

# of moles = mass / molar mass = 0.500 g / 151 g/mol = 0.003311 moles

3) 3 doses * 2 tablets * 0.003311 moles / tablet = 0.020 moles

7 0

2 years ago

What change would you expect on the rate of the SN2 reaction of 1-iodo-2-methylbutane with cyanide ion if the nucleophile concen

n200080 [17]

Answer:

no effect

Explanation:

In an SN2 reaction, the mechanism is bi-molecular and first order in both the alkyl halide and the nucleophile.

Hence the rate of reaction is;

Rate = k [1-iodo-2-methylbutane] [cyanide ion]

Given that it is a bimolecular reaction, if we double the concentration of 1-iodo-2-methylbutane and the concentration of the cyanide ion is halved, the rate of reaction remains the same.

6 0

2 years ago

Calculate the standard entropy of vaporization of ethanol at its boiling point 285 K. The standard molar enthalpy of vaporizatio

Ivanshal [37]

Answer:

standard entropy of vaporization of ethanol = 142.105 J/K-mol

Explanation:

given data

enthalpy of vaporization of ethanol = 40.5 kJ/mol = 40.5 × $10^{3}$ J/mol

entropy of vaporization of ethanol boiling point = 285 K

to find out

standard entropy of vaporization of ethanol

solution

we get here standard entropy of vaporization of ethanol that is expess as

standard entropy of vaporization of ethanol ΔS = $\frac{\Delta H}{T}$ .............1

here ΔH is enthalpy of vaporization of ethanol and T is temperature

put value in equation 1

standard entropy of vaporization of ethanol ΔS = $\frac{40.5*10^3}{285}$

standard entropy of vaporization of ethanol = 142.105 J/K-mol

3 0

3 years ago

Read 2 more answers

A Helium gas in a tube with a volume of 9.583 L under pressure of 4.972 atm at 31.8 c

andre [41]

1.905 moles of Helium gas are in the tube. Hence, option A is correct.

<h3>What is an ideal gas equation?</h3>

The ideal gas law (PV = nRT) relates the macroscopic properties of ideal gases. An ideal gas is a gas in which the particles (a) do not attract or repel one another and (b) take up no space (have no volume).

Calculate the moles of the gas using the gas law,

PV=nRT, where n is the moles and R is the gas constant. Then divide the given mass by the number of moles to get molar mass.

Given data:

P= 4.972 atm

V= 9.583 L

n=?

R= $0.082057338 \;L \;atm \;K^{-1}mol^{-1}$