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The element which would have the lowest electronegativity is: an element with a small number of valence electrons and a large atomic radius.
Atomic radii can be defined as a measure of the size (distance) of the atom of a chemical element such as hydrogen, oxygen, carbon, nitrogen etc, typically from the nucleus to the valence electrons. The atomic radius of a chemical element decreases across the periodic table, typically from alkali metals (group one elements such as hydrogen, lithium and sodium) to noble gases (group eight elements such as argon, helium and neon). Also, the atomic radius of a chemical element increases down each group of the periodic table, typically from top to bottom (column).
Generally, atoms with relatively large atomic radii tend to have a low electronegativity, ionization energy and a low electron affinity.
Valence electrons can be defined as the number of electrons present in the outermost shell of an atom. Thus, number of valence electrons is typically used to determine the chemical properties of elements such as electronegativity.
Electronegativity can be defined as the ability or tendency of the atom of an chemical element to attract any shared pair of electrons.
In conclusion, a chemical element that has small number of valence electrons and a large atomic radius would have the lowest electronegativity.
Find more information: brainly.com/question/24370190
Explanation:
divide the weight in grams by the atomic mass from the periodic table, then multiply the result by Avogadro's number..
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