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Reika [66]
3 years ago
15

Which of the following is the correct formula for barium (II) sulfate?

Chemistry
2 answers:
nasty-shy [4]3 years ago
5 0
BaSO4 is the correct formula for barium (ll) sulfate
balu736 [363]3 years ago
4 0
BaSO4 is the correct formula for barium (ll) sulfate
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A balloon filled with air has a volume of 6.50 L, a pressure of 0.900 atm, and a temperature of 25.0oC. If it is left out overni
kari74 [83]

Answer:

4.92 L

Explanation:

Rearrange ideal gas law and solve.

Change C to K.

- Hope that helps! Please let me know if you need further explanation.

8 0
3 years ago
What quantity in moles of HCl are there in 35.0 mL of 0.350 M HCl?
marta [7]

Answer:

0.0123 moles

Explanation:

Concentration = Moles / Volume of solution

or you can rearrange the formula to get

Moles = concentration (moles/liter)  x  volume of solution (liter)

First convert your volume to L instead of mL.  35mL = 0.035L

moles  =  0.350 moles/liter   x    0.035 liter  (liters cancel out)

moles = 0.0123

5 0
3 years ago
When carbon is burned in air, it reacts with oxygen to form carbon dioxide. When 15.6 g of carbon were burned in the presence of
NeX [460]

Answer: 5.72 g mass of carbon dioxide was produced

Explanation:

C+O_2\rightarrow CO_2

Moles of C =\frac{\text{mass of carbon}}{\text{molar mass of carbon}}=\frac{15.6 g}{12 g/mol}=1.3 moles

Mass of O_2 reacted = 59.1 g - 17.5 g = 41.6 g

Moles of O_2\text{ reacted}=\frac{\text{mass of}O_2}{\text{molar mass of}O_2}=\frac{41.6 g}{32 g/mol}=1.3 moles

According to reaction 1 mole O_2 produces 1 mole of CO_2 then 1.3 mole of O_2 will produce \frac{1}{1}\times 1.3 moles of CO_2

Mass of CO_2:

=Moles of CO_2 × molar mass ofCO_2 = 1.3 ×44 g/mol =

=57.2 grams

5.72 g mass of carbon dioxide was produced

7 0
3 years ago
The compound NaOH dissolves in water to yield ?
Lunna [17]
<span>Hydroxide ions as the only negative ions</span>
7 0
3 years ago
A helium atom has --- protons &amp; --- neutrons ?
inn [45]
1 proton

(found in periodic table)

(atomic mass - atomic number = neutrons
1 - 1 = 0)

0 neutrons
5 0
3 years ago
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