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3 years ago

Which questions would help determine whether an article is scientifically accurate?

Chemistry

2 answers:

trasher [3.6K]3 years ago

6 0

Answer:

Option A and C

Explanation:

When the question A is asked "whether the author's statement is an opinion or fact?" then the answer to this question will definitely help to determine whether the author has written a scientific article or not. If the author states that he has expressed his opinion then such articles cannot not be considered as scientific article.

Likewise if the author has given appropriate and sufficient evidences to prove the fact that he had mentioned in his article then such articles will definitely fall into the category of scientific article. Hence option C is correct.

Question B, E are totally irrelevant

While question D is just a way to analyse whether the author is renowned author who publishes sensible article or he is a new comer. This question is basically to check the authenticity of the author writing skills.

-BARSIC- [3]3 years ago

3 0

I think it would be:
Is the author stating fact or opinion?
Does the author have evidence for the given facts?

Maybe
How many article has the author written before?

Ones you add if you wanted to is
Does the author give any sources? (Like where they got the info)

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How hot, in degrees Celsius, would the air inside the balloon have to get in order for the balloon to lift off the ground? Assum

SVETLANKA909090 [29]

Answer:

The temperature in degress Celsius is 52.25°C

Explanation:

According the equation:

$V(\rho _{a} -\rho _{t})g=mg\\\rho _{a} -\rho _{t}=\frac{n}{V} =\frac{340}{2950} =0.115kg/m^{3}$

$\rho _{t}=\rho _{a} -0.115=1.2-0.115=1.085kg/m^{3}$

The temperature is:

$T=\frac{P}{\rho _{t} R} =\frac{1.013x10^{5} }{1.085*287.05} =325.25K=52.25$ °C

3 0

3 years ago

During one researcher's experiment, the total mass of the gas-generating solid and entire assembly was 52.1487g before the react

irinina [24]

Answer:

43.93 g/mol

Explanation:

The mass of the gas before reaction = 52.1487 g

The mass of the gas after reaction = 52.1098 g

Mass of gas generated = 0.0389 g

Moles of the gas = $8.854\times 10^{-4}\ moles$

The formula for the calculation of moles is shown below:

$moles = \frac{Mass\ taken}{Molar\ mass}$

Thus,

$Molar\ mass = \frac{Mass\ taken}{Moles}$

$Molar\ mass= \frac{0.0389\ g}{8.854\times 10^{-4}\ moles}$

Molar mass of the gas = 43.93 g/mol

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3 years ago

A student requires 2.00 L of 0.100 M NH4NO3 from a 1.75 M NH4NO3 stock solution. What is the correct way to get the solution?

Sonbull [250]

Answer: Measure 114 mL of the 1.75 M solution, and dilute it to 2.00 L.

Explanation:

The number of moles in the solution will remain same on dilution and thus according to Molarity Equation:

$M_1V_1=M_2V_2$

$M_1$ = molarity of first solution

$V_1$ = Volume of first solution

$M_2$ = molarity of second solution

$V_2$ = Volume of second solution

$0.1\times 2.00L=1.75M\times V_2$

$V_2=0.114L=114ml$

Thus 114 ml of 1.75 M solution is taken and the volume is diluted to 2.0 L to make 0.100 M solution.

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3 years ago

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Free_Kalibri [48]

Answer:

i think 40 grams

Explanation:

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