Answer:
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Explanation:
A chemical reaction or physical change is exothermic if heat is released by the system into the surroundings. Because the surroundings are gaining heat from the system, the temperature of the surroundings increases. The sign of \(q\) for an exothermic process is negative because the system is losing heat.
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Answer:
V = 10.3 L
Explanation:
Given data:
Mass of methane = 6.40 g
Volume of CO₂ produced = ?
Temperature = 35°C (35+273 = 308 K)
Pressure = 100.0 KPa (100.0/101 = 0.98 atm)
Solution:
Chemical equation:
CH₄ + 2O₂ → CO₂ + 2H₂O
Number of moles of CH₄:
Number of moles = mass/molar mass
Number of moles = 6.40 g/ 16 g/mol
Number of moles = 0.4 mol
Now we will compare the moles of CO₂ with CH₄.
CH₄ : CO₂
1 : 1
0.4 : 0.4
Volume of CO₂:
Formula:
PV = nRT
0.98 atm ×V = 0.4 mol ×0.0821 atm.L/mol.K × 308 K
0.98 atm ×V = 10.11 atm.L
V = 10.11 atm.L /0.98 atm
V = 10.3 L
Answer:
The correct answer is 1 glycogen degradation would slow down.
Explanation:
Glycogen is the principle storage polysaccharide present in the liver and muscle of human body.
Glycogen contain both alpha-1,4-glycosidic linkage and alpha -1,6-glycosidic linkage.During glycogenolysis some glucose residues are transferred from branch point of the glycogen to its end and thereafter a single glucose residue is linked to the branch point of glycogen by alpha-1,6-glycosidic linkage.
The alpha-1,6-glycosidic linked glucose of glycogen is finally get separated from glycogen by the catalytic activity of alpha-1,6-glycosidase enzyme in the final step of glycogenolysis.
According to the given question if there is no alpha-1,6-glycosidic linkage in the glycogen then glycogen degradation will slow down.
1) 2700 kg/l
2) 13.6 kg/l
3) 0.1578 kg
4) 8921.5 kg/m3
5) 1.59 kg/l
6) 1.84 kg/l
7) 0.21965 kg
8) 11331.9 kg/m3
9) 7.9167 kg/l
10) 238.095 cm3
Just divide the masses by volume to find out the density, multiply the volume with density to find out the mass and divide the mass by density to find out the volume.
To turn the result into SI unit (kg/l), divide the g by 1000 and ml by 1000.
