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mr_godi [17]
3 years ago
6

H2A and BOH are acid and base and they react according to the following balanced equation: H2A(aq) + 2 BOH(aq) → B2A(aq) + 2 H2O

(l) If 0.20 moles of BOH reacted with excess amount of H2A solution and 1500. J of heat was released by the reaction, what is the ∆Hrxn for the reaction as written above?
Chemistry
1 answer:
Rudiy273 years ago
3 0

Answer:

ΔH=15000 J  =  15KJ

Explanation:

In this exercise  you have find the enthalpy of reaction this is the difference between enthalpy of reactans and products,

For the following equation

H2A(aq) + 2 BOH(aq) → B2A(aq) + 2 H2O(l)

We know that 0.20 moles of BOH reacted with excess amount of H2A solution and 1500. J

so,

(2mol/0,2mol)*1500J=15000J

for de reactions exothermics tha enthalpy is negative so:

ΔH=15000 J  =  15KJ

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