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Ksju [112]
3 years ago
14

What direction does an applied force move an object

Physics
2 answers:
Lera25 [3.4K]3 years ago
7 0
Lets say you push a ball from the back, is it gonna come back towards you or go away from you.  So an object will go the same direction that the applied for pushed it 

Hope this helps :)
monitta3 years ago
4 0
The object will move in the direction of the applied force.
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Off course weight because our weight is equal to for e is equal to mg
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A crow is flying horizontally with a constant speed of 2.70m/s when it releases a claim from its beak. The clan lands on the roc
jenyasd209 [6]

Given:

Speed = 2.70 m

Time, t = 2.10 seconds

Let's solve for the following:

• (a) The horizontal component of the velocity.

To find the horizontal component, apply the formula:

V_{ox}=V_o\cos \theta

Where:

Vo is the initial speed = 2.70 m

θ = 0 degrees

Hence, we have:

\begin{gathered} V_{ox}=2.70\cos 0 \\  \\ V_{ox}=2.7\text{ m/s} \end{gathered}

The horizontal component of the velocity just before it lands is 2.70 m/s.

• (b) The vertical component of the velocity.

To find the vertical component, apply the formula:

V_{oy}=V_{0y}-gt=\text{V}_{oy}\text{ sin}\Theta-gt

Where:

g is the acceleration due to gravity = 9.8 m/s²

t is the time = 2.10 s

Hence, we have:

\begin{gathered} V_{oy}=V_{oy}\sin \theta-gt \\  \\ V_{oy}=2.70\sin 0-9.8(2.10) \\  \\ V_{oy}=0-20.58 \\  \\ V_{oy}=-20.58\text{ m/s} \end{gathered}

The vertical component of the velocity just before it lands is -20.58 m/s.

(c) Here, the initial speed is equal to the constant horizontal speed.

Therefore, in part (a) the horizontal component will increase in the x-direction if the speed of the crow is increased.

The initial vertical velocity is 0 m/s in both cases.

Therefore, in part (b) the vertical component will remain constant.

ANSWER:

(a) 2.70 m/s

(b) -20.58

(c) In part (a) the horizontal component will increase, while in part (b) the vertical component will remain constant.

6 0
1 year ago
Match each term to the best description
Ronch [10]

Answer:

Coefficient of friction =  Magnitude depends on the interacting materials

Friction = A force that acts parallel to the surface.

kinetic friction = A force that is constant regardless of the applied force

Normal = A force that acts perpendicular to the surface

Static friction = A force that increases as applied force increases up to some maximum value

Explanation:

Let's define all the forces, and then let's solve the problem.

Normal force:

When an object rests on some place (like a book on the table) the force that causes the book to not fall through the table is called the normal force, which is usually equal to the weight of the object and acts perpendicular to the surface where the object is resting.

Friction force.

When an object moves (or tries to move) parallel to a surface, such that the object is in contact with that surface, there appears a force that opposes to the movement (the force is parallel to the surface, and in the opposite direction to the movement).

And this force can be written as:

F = -N*μ

Where μ is the coefficient of friction and N is the normal force.

If the object is not moving yet (but there is applied a force that would move the object) the coefficient is called the coefficient of static friction which increases in a given range, until it can't keep increasing and the object starts to move, while if the object is moving, the coefficient is called the coefficient of kinetic friction and it is constant, where usually the first one is larger than the second, and these coefficients depend on both materials, the surface one and the object one.

Then we have two friction forces, one called the kinetic friction and the other called the static friction.

Then:

Coefficient of friction =  Magnitude depends on the interacting materials

Friction = A force that acts parallel to the surface.

kinetic friction = A force that is constant regardless of the applied force

Normal = A force that acts perpendicular to the surface

Static friction = A force that increases as applied force increases up to some maximum value

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3 years ago
An object on a spring whose constant is 30. N/m
MrRa [10]

The mass of the object is 0.0076 kg

Explanation:

The frequency of a mass-spring system (simple harmonic motion) is given by

f=\frac{1}{2\pi}\sqrt{\frac{k}{m}}

where

f is the frequency

k is the spring constant

m is the mass

For the mass-spring system in this problem, we know:

k = 30 N/m is the spring constant

f = 10 Hz is the frequency

Solving the equation for m, we find the mass:

m=\frac{k}{(2\pi f)^2}=\frac{30}{(2\pi (10))^2}=0.0076 kg

#LearnwithBrainly

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<em><u>Answer</u></em>

The answer would be B.

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