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Murrr4er [49]
3 years ago
15

After each half-life cycle, of the radioactive nuclei became nonradioactive.

Chemistry
1 answer:
kherson [118]3 years ago
7 0

Answer:

half

Explanation:

i just took the quiz

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What would the products of a double-replacement reaction between KBr and CaO be? (Remember: In double-replacement reactions, the
11111nata11111 [884]

ANSWER

\begin{gathered} \text{ 2KBr }+\text{ CaO }\rightarrow\text{ K}_2O\text{ }+\text{ CaBr}_2 \\ Option\text{ B} \end{gathered}

EXPLANATION

Given that;

The two reactants are KBr and CaO

Double replacement reaction is a type of chemical reaction that occur when two reactants exchange cations and anions to yield new products.

\text{ 2KBr + CaO  }\rightarrow\text{ K}_2O\text{ + CaBr}_2

Therefore, the resulting products of the given data are K2O + CaBr2

The correct answer is option B

4 0
1 year ago
3. The scientific study of how organisms are classified is called _____.
Vilka [71]
Hey mate!

Taxonomy is the <span>study of classification of organisms. Therefore, your answer is A.

Hope this helps!</span>
3 0
3 years ago
Choose the pair in which the components have the same charge. question 6 options: a proton and a hydrogen atom a hydrogen atom a
worty [1.4K]

Answer:

           A Neutron and a Hydrogen Atom

Explanation:

                   Hydrogen atom having an atomic mass of 1.008 amu consists of one proton and one electron. Hence, the +ve and -ve charges cancels out and makes the hydrogen atom a neutral specie.

                    Also, we know that neutron is neutral sub particle while, proton and electron are positively and negatively charged respectively. Therefore, a neutral neutron having no charge becomes equal to hydrogen atom having zero charge due to cancellation of both +ve and -ve charges.

8 0
3 years ago
Help please
gogolik [260]

Answer:

16 km/2 sec=8km/sec

Explanation:

4 0
2 years ago
Determine the concentration of a solution prepared by diluting 25.0 ml of a stock 0.188 m sr(no3)2 solution to 150.0 ml
o-na [289]
We can use the following equation to calculate the concentration of diluted solution.
c1v1 = c2v2 
where c1 is concentration and v1 is volume of stock solution, which is the more concentrated solution.
c2 is concentration and v2 is the volume of diluted solution.
substituting the values in the equation,
0.188 M x 25.0 mL = c2 x 150.0 mL 
c2 = 0.0313 M
concentration of diluted solution is 0.0313 M
8 0
3 years ago
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