Answer:
FeI2
Anode
Fe^2+
Cathode
I2
K3PO4
Anode
H^+ and K^+
Cathode
H2
Explanation:
In electrolysis, there are two electrodes present, the cathode and the anode. The anode is the positive electrode. This is where oxidation occurs and positive ions are formed. Species give up a electrons at the anode and the electrons travel towards the cathode.
At the cathode (negative electrode where reduction occurs), species accept electrons according to their position in the electrochemical series. In the case of K3PO4, both hydrogen and potassium ions arrive at the cathode but hydrogen in preferentially discharged due to the position of the two ions in the electrochemical series.
Answer:
<h2>2.89 × 10²⁴ particles</h2>
Explanation:
The number of particles can be found by using the formula
N = n × L
where n is the number of moles
N is the number of entities
L is the Avogadro's constant which is 6.02 × 10²³ entities
We have
N = 4.8 × 6.02 × 10²³
We have the final answer as
<h3>2.89 × 10²⁴ particles</h3>
Hope this helps you
Answer is: no, <span>potassium iodide has low solubility in cyclohexane.
</span>Potassium iodide (KI) is ionic compound, salt, that dissolve good in polar solvents (for example water), but it is very low soluble in non-polar solvents (in this example cyclohexane C₆H₁₂).
<span>Cyclohexane has zero net polarity, because it is a symmetric molecule, with sp2 hybridization of carbon.</span>
12 grams of methane is one mole. So there are N(Avogadro)=6.22 x 10^23 molecules in one mole of methane
There would be about 1.67 x 10^25 oxygen atoms and about 3.34 x 10^25 hydrogen atoms.
