Answer:
[HI] = 0.264M
Explanation:
Based on the equilibrium:
2HI(g) ⇄ H₂(g) + I₂(g)
It is possible to define Kc of the reaction as the ratio between concentration of products and reactants using coefficients of each compound, thus:
<em>Kc = 0.0156 = [H₂] [I₂] / [HI]²</em>
<em />
As initial concentration of HI is 0.660mol / 2.00L = <em>0.330M, </em>the equlibrium concentrations will be:
[HI] = 0.330M - 2X
[H₂] = X
[I₂] = X
<em>Where X is reaction coefficient.</em>
<em />
Replacing in Kc:
0.0156 = [X] [X] / [0.330M - 2X]²
0.0156 = X² / [0.1089 - 1.32X + 4X²
]
0.00169884 - 0.020592 X + 0.0624 X² = X²
0.00169884 - 0.020592 X - 0.9376 X² = 0
Solving for X:
X = - 0.055 → False solution, there is no negative concentrations
X = 0.0330 → Right solution.
Replacing in HI formula:
[HI] = 0.330M - 2×0.033M
<h3>[HI] = 0.264M</h3>
Answer:your answer is 0.95
Explanation:
Because you put the number down if it is in the hundreds then put into a decimal that it is in the hundredths:)
Answer:
134.8 mmHg is the vapor pressure for solution
Explanation:
We must apply the colligative property of lowering vapor pressure, which formula is: P° - P' = P° . Xm
P° → Vapor pressure of pure solvent
P' → Vapor pressure of solution
Xm → Mole fraction for solute
Let's determine the moles of solute and solvent
17.5 g . 1 mol/180 g = 0.0972 moles
82 g . 1mol / 32 g = 2.56 moles
Total moles → moles of solute + moles of solvent → 2.56 + 0.0972 = 2.6572 moles
Xm → moles of solute / total moles = 0.0972 / 2.6572 = 0.0365
We replace the data in the formula
140 mmHg - P' = 140 mmHg . 0.0365
P' = - (140 mmHg . 0.0365 - 140mmHg)
P' = 134.8 mmHg
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The ________ orbital is degenerate with 5py in a many-electron atom.
<h2>
5px is the correct answer</h2>
