The 102N acting on the ropes being pulled by eric and kim have some of that force acting horizontally, and some of it vertically. By visualizing it as a right angled triangle, with the hypotenuse the length of the diagonal force, and each side the length of the horizontal and vertical forces, you can use trigonometry to calculate the length of the vertical force. You are told that it is at an angle of 30 with the vertical rope, therefore you know the length of the hypotenuse, and the angle between it and the vertical force, so using trig: (vertical force=x)
x/102=cos(30)
x=102*cos(30)
x=88.33
Therefore the diagonal ropes give a vertical force of 88.33N, and the centre rope, as it acts vertically, gives a vertical force of all 102N. The total:
88.33*2+102=278.66N
I don't know if this is very clear, I hope its good enough to help. If you don't understand, just ask, and I can answer any questions!!! :)
Answer:
Acceleration is 7.990487515m/s²
Initial velocity is 0m.s
Explanation:
s=ut+(1/2)at²
210=0(7.25)+(1/2)a(7.25²)
210=26.28125a
∴a=7.990487515m/s²
'Vi' or 'u' is the inital speed. Since it starts from rest, this equals 0.
The shirt absorbs the sunlight, so it appears white. All the light is reflected, so the shirt appears white. The sunlight refracts when it hits the shirt, so the shirt appears white.
Answer:
λ = 5.65m
Explanation:
The Path Difference Condition is given as:
δ=
;
where lamda is represent by the symbol (λ) and is the wavelength we are meant to calculate.
m = no of openings which is 2
∴δ= 
n is the index of refraction of the medium in which the wave is traveling
To find δ we have;
δ= 
δ= 
δ= 
δ= 
δ= 
δ= 
δ= 82.15 -73.68
δ= 8.47
Again remember; to calculate the wavelength of the ocean waves; we have:
δ=
δ= 8.47
8.47 =
λ = 
λ = 5.65m
