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Ostrovityanka [42]
2 years ago
13

What’s the atomic number for magnesium

Physics
1 answer:
zmey [24]2 years ago
5 0

Answer:

12

Explanation:

Symbol: Mg

Atomic mass: 24.305 u

Atomic number: 12

Density: 1.738 g/cm³

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If a marble is released from a height of 10 meters how long would it take to hit the ground?
zlopas [31]
S = ut + 0.5at^2 

<span>10 = 0 + 0.5(9.81)t^2 {and if g = 10 then t^2 = 2 so t ~1.414}  </span>

<span>t^2 ~ 2.04 </span>

<span>t ~ 1.43 seconds</span>
3 0
3 years ago
What is a Pulley why is it used​
aleksley [76]

Answer:

A simple pulley is a wheel with a rope that allows you to pull one end and have it lift whatever is on the other end. A modern, common example of this is a crane, often used in construction.

Explanation:

4 0
2 years ago
Anyone know the answer ?
nata0808 [166]

Answer:

d

Explanation:

4 0
2 years ago
Read 2 more answers
Please help
WITCHER [35]

Gravity is the force that pulls you down.
(This is kind of a duh! question ... How do we know
which way is "down" ?  We feel gravity, and we call
that the "down" direction.)

Magnetic force holds things to fridge doors.

Contact forces need to touch something in order to
exert their force.
Example:  Gravity is NOT a contact force.

I don't know about "rubbing things away".
This might be a description of friction, but if so,
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Buoyant force is what keeps floating things floating.

Air resistance slows things down when they move in air.

4 0
3 years ago
Can someone help?
laila [671]

Answer:

i) 21 cm

ii) At infinity behind the lens.

iii) A virtual, upright, enlarged image behind the object

Explanation:

First identify,

object distance (u) = 42 cm (distance between  object and lens, 50 cm - 8 cm)

image distance (v) = 42 cm (distance between  image and lens, 92 cm - 50 cm)

The lens formula,

\frac{1}{v} -\frac{1}{u} =\frac{1}{f}

Then applying the new Cartesian sign convention to it,

\frac{1}{v} +\frac{1}{u} =\frac{1}{f}

Where f is (-), u is (+) and  v is (-) in  all 3  cases. (If not values with signs have to considered, this method that need will not arise)

Substituting values you get,

i) \frac{1}{42} +\frac{1}{42} =\frac{1}{f}\\\frac{2}{42} =\frac{1}{f}

f = 21 cm

ii) u =21 cm, f = 21 cm v = ?

Substituting in same equation\frac{1}{v} =\frac{1}{21} =\frac{1}{21} \\\\\frac{1}{v} = 0\\

  v ⇒ ∞ and image will form behind the lens

iii) Now the object will be within the focal length of the lens. So like in the attachment, a virtual, upright, enlarged image behind the object.

7 0
3 years ago
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