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MissTica
3 years ago
12

The force known as the collisions of gas particles of matter is known as __________.

Chemistry
1 answer:
bazaltina [42]3 years ago
6 0

Answer: the answer is combustion

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The rate at which energy is transferred is called a power b kinetic energy c work d time
grandymaker [24]
This is one of the definitions that is used to define C. Work. It is a change in energies from one form to another within some time frame.
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3 years ago
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0.17 M KCHO2 Find the pH
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I believe the pH is 7. If you would like me to explain comment.
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3 years ago
A 58.5 g sample of glass is put into a calorimeter (see sketch at right) that contains 250.0 g of water. The glass sample starts
Ket [755]

Answer:

The specific heat capacity of glass is 0.70J/g°C

Explanation:

Heat lost by glass = heat gained by water

Heat lost by glass = mass × specific heat capacity (c) × (final temperature - initial temperature) = 58.5×c×(91.2 - 21.7) = 4065.75c

Heat gained by water = mass × specific heat capacity × (final temperature - initial temperature) = 250×4.2×(21.7 - 19) = 2835

4065.75c = 2835

c = 2835/4065.75 = 0.70J/g°C

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3 years ago
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Convert 349.5 inches to meters
Brut [27]
1 inch is equivalent to 0.0254 meters. To find the answer, multiply the number of inches by 0.0254.
349.5 x 0.0254 = 8.8773

 
3 0
3 years ago
When a lead acid car battery is recharged by the alternator, it acts essentially as an electrolytic cell in which solid lead(II)
katen-ka-za [31]

Answer:

3.81 g Pb

Explanation:

When a lead acid car battery is recharged, the following half-reactions take place:

Cathode: PbSO₄(s) + H⁺ (aq) + 2e⁻ → Pb(s) + HSO₄⁻(aq)  

Anode: PbSO₄(s) + 2 H₂O(l) → PbO₂(s) + HSO₄⁻(aq) + 3H⁺ (aq) + 2e⁻

We can establish the following relations:

  • 1 A = 1 c/s
  • 1 mole of Pb(s) is deposited when 2 moles of e⁻ circulate.
  • The molar mass of Pb is 207.2 g/mol
  • 1 mol of e⁻ has a charge of 96468 c (Faraday's constant)

Suppose a current of 96.0A is fed into a car battery for 37.0 seconds. The mass of lead deposited is:

37.0s.\frac{96.0c}{s} .\frac{1mole^{-} }{96468c} .\frac{1molPb}{2mole^{-} } .\frac{207.2gPb}{1molPb} =3.81gPb

6 0
3 years ago
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