<span>On a molar a basis, the most effective bleaching agent kbro3 has more oxygen, but due to the bromine, it would make things look yellowish. The bromine would counteracts the bleaching effect. As we all know, bleach is naocl or hypochlorite</span>
Answer:
Only
gives spontaneous reaction.
Explanation:
A redox reaction will be spontaneous if standard reduction potential (
) of the reaction is positive. Because it leads to negative standard gibbs free energy change (
), which is a thermodynamic condition for spontaneity of a reaction.
![E^{0}=E^{0}(reduction)-E^{0}(oxidation)](https://tex.z-dn.net/?f=E%5E%7B0%7D%3DE%5E%7B0%7D%28reduction%29-E%5E%7B0%7D%28oxidation%29)
Where
and
represents standard reduction potential of reduction half cell and standard reduction potential of oxidation half cell.
(1) Oxidation:
; ![E_{Mg^{2+}\mid Mg}^{0}=-2.38V](https://tex.z-dn.net/?f=E_%7BMg%5E%7B2%2B%7D%5Cmid%20Mg%7D%5E%7B0%7D%3D-2.38V)
Reduction:
; ![E_{Fe^{3+}\mid Fe}^{0}=-0.04V](https://tex.z-dn.net/?f=E_%7BFe%5E%7B3%2B%7D%5Cmid%20Fe%7D%5E%7B0%7D%3D-0.04V)
So, ![E^{0}=E_{Fe^{3+}\mid Fe}^{0}-E_{Mg^{2+}\mid Mg}^{0}=(-0.04+2.38)V=2.34V](https://tex.z-dn.net/?f=E%5E%7B0%7D%3DE_%7BFe%5E%7B3%2B%7D%5Cmid%20Fe%7D%5E%7B0%7D-E_%7BMg%5E%7B2%2B%7D%5Cmid%20Mg%7D%5E%7B0%7D%3D%28-0.04%2B2.38%29V%3D2.34V)
Hence this pair will give spontaneous reaction.
(2) Similarly as above, ![E^{0}=E_{Pb^{2+}\mid Pb}^{0}-E_{Au^{+}\mid Au}^{0}=(-0.13-1.69)V=-1.82 V](https://tex.z-dn.net/?f=E%5E%7B0%7D%3DE_%7BPb%5E%7B2%2B%7D%5Cmid%20Pb%7D%5E%7B0%7D-E_%7BAu%5E%7B%2B%7D%5Cmid%20Au%7D%5E%7B0%7D%3D%28-0.13-1.69%29V%3D-1.82%20V)
Hence this pair will give non-spontaneous reaction.
(3) Similarly as above, ![E^{0}=E_{Ag^{+}\mid Ag}^{0}-E_{Br_{2}\mid Br^{-}}^{0}=(0.80-1.07)V=-0.27 V](https://tex.z-dn.net/?f=E%5E%7B0%7D%3DE_%7BAg%5E%7B%2B%7D%5Cmid%20Ag%7D%5E%7B0%7D-E_%7BBr_%7B2%7D%5Cmid%20Br%5E%7B-%7D%7D%5E%7B0%7D%3D%280.80-1.07%29V%3D-0.27%20V)
Hence this pair will give non-spontaneous reaction.
(4) Similarly as above, ![E^{0}=E_{Li^{+}\mid Li}^{0}-E_{Cr^{3+}\mid Cr}^{0}=(-3.04+0.74)V=-2.30 V](https://tex.z-dn.net/?f=E%5E%7B0%7D%3DE_%7BLi%5E%7B%2B%7D%5Cmid%20Li%7D%5E%7B0%7D-E_%7BCr%5E%7B3%2B%7D%5Cmid%20Cr%7D%5E%7B0%7D%3D%28-3.04%2B0.74%29V%3D-2.30%20V)
Hence this pair will give non-spontaneous reaction.
Erm i’m afraid we need the list
Answer:
When the two atoms move towards each other a compound is formed by sharing electron pairs supplied by each of the atoms to enable them have the stable 8 (octet) valency electrons in their outermost shell
Explanation:
The electronic configuration of the given element can be written as follows;
1s²2s²2p⁴
The given electronic configuration is equivalent to that of oxygen, therefore, we have;
The number of electrons in the valence shell = 2 + 4 = 6 electrons
Therefore, each atom requires 2 electrons to complete its 8 (octet) electrons in the outermost shell
When the two atoms move towards each other, they react and combine to form a compound by sharing 4 electrons, 2 from each atom, such that each atom can have an extra 2 electrons in its outermost orbit in the newly formed compound and the stable octet configuration is attained by each of the atoms in the newly formed compound.
Answer:
1 - 3
Explanation:
- Look to see where metals are on the periodic table then look at what group they are in. The group tells you the number of valence electrons. Ex. 1A has one valence electron.
- Hope this helped! If you need a further explanation please let me know.