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guapka [62]
3 years ago
6

Emily is a competitive swimmer. Why does wearing a swim cap help Emily swim faster?

Chemistry
1 answer:
faust18 [17]3 years ago
8 0
Well the problem is that Emily is capping. PERIODT jpjp
the answer is
B) the cap keeps the hair out of her eyes

I SWEAR IF IM WRONG THAN EMILY CAPPING CUZ MY CAP DECTOR IS GOING OFF
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Which environmental conditions contribute most to the spread of bacteria?
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Explanation: Bacteria thrives in warm and moist environments.
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Empirical formula of n3h9
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Empirical formula is nh3

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The emission of a Beta particle has the effect of...? A. Decreasing mass by one unit /B.Increasing mass by one unit / C. - No ch
vodomira [7]
The emission of a beta particle has the effect of : C. No change in mass

basically, beta particle has a very very little mass compared to the proton and  neutrons, so  little to the point that it never considered as a change in mass. But it does decreases the charge of atom

hope this helps

3 0
3 years ago
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What is sodium chloride​
DedPeter [7]

Answer:

Sodium chloride, commonly known as salt, is an ionic compound with the chemical formula NaCl, representing a 1:1 ratio of sodium and chloride ions.

Explanation:

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5 0
3 years ago
A laboratory analysis of a 100 g sample finds it is composed of 1.8 g hydrogen, 56.1 g sulfur, and 42.1 g oxygen. What is its em
Neporo4naja [7]

Answer: The empirical formula is H_2S_2O_3

Explanation:

If percentage are given then we are taking total mass is 100 grams.

So, the mass of each element is equal to the percentage given.

Mas of H = 1.8 g

Mass of S = 56.1 g

Mass of O = 42.1 g

Step 1 : convert given masses into moles.

Moles of H =\frac{\text{ given mass of H}}{\text{ molar mass of H}}= \frac{1.8g}{1g/mole}=1.8moles

Mass of S =\frac{\text{ given mass of S}}{\text{ molar mass of S}}= \frac{56.1g}{32g/mole}=1.8moles

Moles of O=\frac{\text{ given mass of O}}{\text{ molar mass of O}}= \frac{42.1g}{16g/mole}=2.6moles

Step 2 : For the mole ratio, divide each value of moles by the smallest number of moles calculated.

For H = \frac{1.8}{1.8}=1

For S = \frac{1.8}{1.8}=1

For O =\frac{2.6}{1.8}=1.5

Converting to whole number ratios

The ratio of H: S: O= 2: 2: 3

Hence the empirical formula is H_2S_2O_3

7 0
3 years ago
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