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Mnenie [13.5K]
3 years ago
11

Which describes the motion of the media for a surface wave?

Physics
2 answers:
monitta3 years ago
3 0

the motion is both parallel and perpendicular to wave direction B

oksian1 [2.3K]3 years ago
3 0

Answer:

B is correct

Explanation:

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In a solution if substance A makes up 1%, substance B makes up 9%, substance C makes up 20% and substance D makes up 70%, which
SIZIF [17.4K]
From the description of the substances, the best answer would be option A. Substance D would generally function as a solvent because it has the largest composition in a solution. A solvent in a solution has the highest percent composition among all components involved. Having a composition of more than 50% would mean that a substance is the solvent.
8 0
3 years ago
You are standing 1 meter from a squawking parrot. If you move to a distance three meters away, the sound
spayn [35]
Use the inverse square law, thus if you move a distance of 3m away, the sound intensity decrease by 1/3^2= 1/9
5 0
3 years ago
Read 2 more answers
magnitude of velocity does not change but the direction changes. Can we say that it is an accelerated motion?
Olenka [21]

Answer:

MRCORRECT has answered the question

Explanation:

Since velocity is a vector, it can change either in magnitude or in direction. Acceleration is therefore a change in either speed ordirection, or both. Keep in mind that althoughacceleration is in the direction of the changein velocity, it is not always in the direction ofmotion.

4 0
3 years ago
Find a numerical value for rhoearth, the average density of the earth in kilograms per cubic meter. Use 6378km for the radius of
mylen [45]

Answer:

density = 5520 kg/m^3

Explanation:

given that

radius of earth = 6378 km

G = 6.67 x 10⁻¹¹ m³/kg.s²

g = 9.80 m/s²

we know,

g = \dfrac{GM}{r^2}

mass of earth

M = \dfrac{gr^2}{G}

M = \dfrac{9.8 \times (6378 \times 10^3)^2}{6.67 \times 10^{-11}}

M = 5.972 x 10²⁴ kg

density =\dfrac{mass}{volume}

V = volume of the earth = 4/3πr³

V = 4/3 x 3.14 x (6378  x 10³)³

V = 1.08 x 10²¹ m³

density = \dfrac{5.972\times 10^{24}}{1.08\times 10^{21}}

density = 5.52 x 10³  kg/m^3

density = 5520 kg/m^3

8 0
3 years ago
Calculate the electric field strength at a point at which a test charge of 0.30 coulombs experiences a force of 5.0 newtons.
SVEN [57.7K]

The strength of electric field E is 17 N / C.

<u />

<u>Explanation:</u>

Electric field strength is defined as the force per unit charge acting at a point in the given field. The equation for the strength of the electric field is given by

                     E = F / q

where E represents the electric field strength,

           F represents the force in newton,

           q represents the charge in coulomb.

Given the charge q = 0.30 coulombs

                   force F = 5.0 N

Electric field strength E = force / charge

                                        = 5.0 / 0.30

                                    E  = 16.66 = 17 N / C.

5 0
3 years ago
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