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Mnenie [13.5K]
3 years ago
11

Which describes the motion of the media for a surface wave?

Physics
2 answers:
monitta3 years ago
3 0

the motion is both parallel and perpendicular to wave direction B

oksian1 [2.3K]3 years ago
3 0

Answer:

B is correct

Explanation:

You might be interested in
Una bailarina de 50 kg, se apoya sobre la punta de uno de sus pies. Sabiendo que la superficie de la punta es de 6 cm2, ¿Qué pre
fiasKO [112]

Answer:

17kg

Explanation:

3 0
3 years ago
(II) A 0.450-kg hockey puck, moving east with a speed of 5.80 m/s, has a head-on collision with a 0.900-kg puck initially at res
Alisiya [41]

Answer:

The second puck moves with a speed of 3.867 m/s due east and the first puck moves with a speed of 1.933 m/s, but in the Western direction after collision.

Explanation:

Let the mass of the first hockey puck = m₁ = 0.45 kg

Mass of the resting puck = m₂ = 0.90 kg

Velocity of the first hockey puck = v₁ = 5.80î m/s; magnitude = 5.80 m/s

Velocity of resting puck = v₂ = 0 m/s

Mass of the two pucks are the same after collision.

Velocity of first puck after collision = v₃ = ?

Velocity of second puck after collision = v₄ = ?

In an elastic collision, both momentum and kinetic energy are conserved.

Momentum before collision = momentum after collision

Momentum before collision

m₁v₁ + m₂v₂ = (0.45 × 5.8) + (0.9 × 0) = 2.61 kgm/s

Momentum after collision

m₁v₃ + m₂v₄ = 0.45v₃ + 0.9v₄

So, according to the law of conservation of Momentum,

2.61 = 0.45v₃ + 0.9v₄ (eqn 1)

Kinetic energy before collision = kinetic energy after collision

Kinetic energy before collision = (m₁v₁²/2) + (m₂v₂²/2) = (0.45 × 5.8²/2) + (0.9 × 0²/2) = 7.569 J

Kinetic energy after collision = (m₁v₃²/2) + (m₂v₄²/2) = (0.45v₃²/2) + (0.9v₄²/2) = 0.225v₃² + 0.45v₄²

Since kinetic energy is conserved,

7.569 = 0.225v₃² + 0.45v₄² (eqn 2)

2.61 = 0.45v₃ + 0.9v₄ (eqn 1)

7.569 = 0.225v₃² + 0.45v₄² (eqn 2)

Make v₃ the subject of formula from eqn 1,

v₃ = (2.61 - 0.9v₄)/0.45 = (5.8 - 2v₄)

Substitute the value of v₃ into eqn 2

7.569 = 0.225(5.8 - 2v₄)² + 0.45v₄²

7.569 = 0.225(33.64 - 23.2v₄ + 4v₄²) + 0.45v₄²

7.569 = 7.569 - 5.22v₄ + 0.9v₄² + 0.45v₄²

1.35v₄² - 5.22v₄ = 0

v₄² - 3.867v₄ = 0

v₄ (v₄ - 3.867) = 0

v₄ = 0 m/s or v₄ = 3.867 m/s

If v₄ = 0 m/s,

v₃ = (5.8 - 2v₄) = [5.8 - 2(0)] = 5.8 m/s

If v₄ = 3.867 m/s

v₃ = (5.8 - 2v₄) = [5.8 - 2(3.867)] = - 1.933 m/s

The (v₃,v₄) answers are (5.8,0) and (-1.933,3.867). Since the collision was stated to be elastic, the realistic answer is the (-1.933, 3.867) answer.

So, the answer is interpreted as,

The second puck moves with a speed of 3.867 m/s due east and the first puck moves with a speed of 1.933 m/s, but in the Western direction after collision.

4 0
3 years ago
A bullet of mass 0.016 kg traveling horizontally at a speed of 280 m/s embeds itself in a block of mass 3 kg that is sitting at
ivanzaharov [21]

(a) 1.49 m/s

The conservation of momentum states that the total initial momentum is equal to the total final momentum:

p_i = p_f\\m u_b + M u_B = (m+M)v

where

m = 0.016 kg is the mass of the bullet

u_b = 280 m/s is the initial velocity of the bullet

M = 3 kg is the mass of the block

u_B = 0 is the initial velocity of the block

v = ? is the final velocity of the block and the bullet

Solving the equation for v, we find

v=\frac{m u_b}{m+M}=\frac{(0.016 kg)(280 m/s)}{0.016 kg+3 kg}=1.49 m/s

(b) Before: 627.2 J, after: 3.3 J

The initial kinetic energy is (it is just the one of the bullet, since the block is at rest):

K_i = \frac{1}{2}mu_b^2 = \frac{1}{2}(0.016 kg)(280 m/s)^2=627.2 J

The final kinetic energy is the kinetic energy of the bullet+block system after the collision:

K_f = \frac{1}{2}(m+M)v^2=\frac{1}{2}(0.016 kg+3 kg)(1.49 m/s)^2=3.3 J

(c) The Energy Principle isn't valid for an inelastic collision.

In fact, during an inelastic collision, the total momentum of the system is conserved, while the total kinetic energy is not: this means that part of the kinetic energy of the system is losted in the collision. The principle of conservation of energy, however, is still valid: in fact, the energy has not been simply lost, but it has been converted into other forms of energy (thermal energy).

4 0
3 years ago
A pulse is sent down a rope that is tied to a wall.
muminat
The answer will be B
8 0
3 years ago
Read 2 more answers
Soil is best described as _______. A. A pure substance B. A compound C. A mixture D. An element
Likurg_2 [28]
Soil is composed of small pieces of a variety of materials, so it is a heterogeneous mixture. The answer would be C (mixture) :)
3 0
3 years ago
Read 2 more answers
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