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Kryger [21]
3 years ago
11

If a sound increases 5 dB, the sound becomes _______ times louder.

Physics
2 answers:
Natasha2012 [34]3 years ago
7 0

Answer:

the right answer is A. five

Explanation:

i just took the test :)

viva [34]3 years ago
3 0
Well, I'll try to write the formula in a way that's not confusing,
but I'm afraid it might be slightly confusing anyway.

When you're working with dB, the basic rule is

       A change of 10 dB means either multiplying or dividing by 10 .

     Multiply something by 10  ==>  it increases by 10 dB.
     Divide something by 10   ==>  it decreases by 10 dB.

It turns out that another way to write all of this is . . .

     An increase of 10 dB ===> multiply the original amount by 10¹ 
     An increase of 20 dB ===> multiply the original amount by 10²
     An increase of, say, 7 dB ===> multiply the original amount by 10⁰·⁷

     A decrease of 10 dB ===> multiply the original amount by 10⁻¹
     A decrease of 30 dB ===> multiply the original amount by 10⁻³
     A decrease of, say, 13 dB ===> multiply the original amount by 10⁻¹·³

This question says:  The sound increases by  5 dB .

That means the original 'intensity' or 'power' of the sound
is multiplied by
                           10⁰·⁵  =  √10  =  about 3.162 (rounded) . 

From the choices listed, the closest one is  (c).
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Setler [38]

Answer:

<h2>The answer is 90 kg</h2>

Explanation:

In order to find the mass of the football we use the formula

m =  \frac{p}{v}  \\

where

p is the momentum

v is the velocity

We have

m =  \frac{630}{7}  \\

We have the final answer as

<h3>90 kg</h3>

Hope this helps you

5 0
3 years ago
Which of the following best describes a coastal plain?
evablogger [386]
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5 0
2 years ago
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saw5 [17]

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3 0
3 years ago
Compare the force of air resistance and the force of gravity on an object falling at its terminal velocity.
Sholpan [36]
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7 0
3 years ago
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maw [93]
 <span>This problem is relatively simple, in order to solve this problem the only formula you need to know is the formula for friction, which is: 

Ff = UsN 

where Us is the coefficient of static friction and N is the normal force. 

In order to get the crate moving you must first apply enough force to overcome the static friction: 

Fapplied = Ff 

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43/0.11 = N = 390.9 which is approximately 391 or C. 3.9x10^2</span>
7 0
3 years ago
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