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Kryger [21]
3 years ago
11

If a sound increases 5 dB, the sound becomes _______ times louder.

Physics
2 answers:
Natasha2012 [34]3 years ago
7 0

Answer:

the right answer is A. five

Explanation:

i just took the test :)

viva [34]3 years ago
3 0
Well, I'll try to write the formula in a way that's not confusing,
but I'm afraid it might be slightly confusing anyway.

When you're working with dB, the basic rule is

       A change of 10 dB means either multiplying or dividing by 10 .

     Multiply something by 10  ==>  it increases by 10 dB.
     Divide something by 10   ==>  it decreases by 10 dB.

It turns out that another way to write all of this is . . .

     An increase of 10 dB ===> multiply the original amount by 10¹ 
     An increase of 20 dB ===> multiply the original amount by 10²
     An increase of, say, 7 dB ===> multiply the original amount by 10⁰·⁷

     A decrease of 10 dB ===> multiply the original amount by 10⁻¹
     A decrease of 30 dB ===> multiply the original amount by 10⁻³
     A decrease of, say, 13 dB ===> multiply the original amount by 10⁻¹·³

This question says:  The sound increases by  5 dB .

That means the original 'intensity' or 'power' of the sound
is multiplied by
                           10⁰·⁵  =  √10  =  about 3.162 (rounded) . 

From the choices listed, the closest one is  (c).
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A very small object with mass 8.30×10-9 kg and positive charge 6.90×10-9 C is projected directly toward a very large insulating
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V=E\Delta x

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K=qV

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7 0
3 years ago
NUMBER 8. NOWWWWWWWW
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