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Hitman42 [59]
3 years ago
14

| 12. Which of the following values is equal to one microfarad

Physics
1 answer:
goldfiish [28.3K]3 years ago
3 0

For this case we have that by definition, the word "micro", according to the International System, is a prefix that indicates a factor of10^ {-6}. It is represented with the symbol:  μ

Therefore, we have that a micro farad is represented as

1 * 10^{ -6} F

Answer:

1 * 10^{ -6} F

Option A

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Two billiard balls move toward each other on a table. The mass of the number three ball, m1, is 5 g with a velocity of 3 m/s. Th
marishachu [46]

Answer:

+5.7 m/s

Explanation:

According to the law of conservation of momentum is that the momentum before the collision is equal to the momentum after the collision. In an equation form it would look like this:

M₁V₁+M₂V₂ = M₁V₁'+M₂V₂'

Where:

M₁ = mass of object 1 (kg)

V₁ = velocity of object 1 before the collision (m/s)

V₁' = Final velocity of object 1 after the collision (m/s)

M₂ = mass of object 2 (kg)

V₂ = velocity of object 2 before the collision (m/s)

V₂' = Final velocity of object 2 after the collision (m/s)

According to your problem you have the following given:

M₁ = 5 g = 0.005kg

V₁ = 3 m/s

V₁' = -5m/s (It bounced off so it is going the other direction)

M₂ = 6g = 0.006kg

V₂ = -1 m/s (It is coming from the opposite direction of the 3-ball)

V₂' = ?

So we plug in what we know and solve for what we don't know.

M_1V_1+M_2V_2 = M_1V_1' + M_2V_2'\\\\(0.005kg)(3m/s)+(0.006kg)(-1m/s) = (0.005kg)(5m/s)+(0.006kg)(V_2')\\\\(0.015kg\cdot m/s)+(-0.006kg\cdot m/s)=(-0.025kg\cdot m/s)+(0.006kg)(V_2')\\\\0.009kg\cdot m/s+0.025kg\cdot m/s = (0.006kg)(V_2')\\\\\dfrac{0.034kg\cdot m/s}{0.006kg} = V_2'\\\\5.7m/s = V_2'

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This means that the shadow of the moon is also moving towards the east. That's why the eclipse moves towards the east (it follows the lunar shadow).
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