Answer:
The correct row is B.
Explanation:
The formation of the magnesium ion, Mg²⁺, comes from the removal of 2 electrons from the valence shell of the magnesium atom.<em> </em>Since the remotion is of electrons, the nucleus of the atom remains the same, so the number of protons and the number of neutrons does not change.<em> </em>
If the number of proton change, then the atom also change, since the identity of an atom is related to the atomic number which is the same to the proton number.
Now, if the number of neutrons changes, then we would be in the presence of an isotope of the magnesium atom.
Therefore, the correct row is B.
I hope it helps you!
Answer:
moles = 36/180 = 0.2 moles
molarity = 0.2/2 = 0.1 mol/dm3
Answer:
The answer is c,F has a smaller radius than F− because F− has an additional energy shell.
Explanation:
if correct mark brainliest
The chemical reaction would be:
<span>CuSO4(aq) + NaOH(aq) = Cu(OH)2(s) + Na2SO4(aq)
One observation would be the formation of a precipitate since one of the products is not readily soluble to aqueous solution. A formation of a blue precipitate will be observed.</span>
Answer:
b. Two moles of thiosulfate anion needed to react with one mole of hypochlorite anion.
Explanation:
1. Hypochlorite with iodide
2I⁻ ⟶ I₂ + 2e⁻
<u>ClO⁻ + 2H⁺ + 2e⁻ ⟶ Cl⁻ + H₂O </u>
2I⁻ + ClO⁻ + 2H⁺ ⟶ I₂ + Cl⁻ + H₂O
2. Thiosulfate with iodine
2S₂O₃²⁻ ⟶ S₄O₆²⁻ + 2e⁻
<u> I₂ + 2e⁻ ⟶ 2I⁻ </u>
2S₂O₃²⁻ + I₂ ⟶ S₄O₆²⁻ + 2I⁻
3. Sum of the reactions
2I⁻ + ClO⁻ + 2H⁺ ⟶ I₂ + Cl⁻ + H₂O
<u> 2S₂O₃²⁻ + I₂ ⟶ S₄O₆²⁻ + 2I⁻ </u>
2I⁻ + ClO⁻ + 2S₂O₃²⁻ + 2H⁺ ⟶ I₂ + Cl⁻ + S₄O₆²⁻ + H₂O
4. Molar ratio
S₂O₃²⁻:ClO⁻ = 2:1
