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tester [92]
3 years ago
14

A stationary object has no forces acting on it. Question 8 options: True or False

Chemistry
2 answers:
svp [43]3 years ago
4 0
Your answer would be false. Hope this helps!
Gwar [14]3 years ago
3 0
False because gravity must be acting upon it. :)
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Plz do it ..i am confused​
Lubov Fominskaja [6]

Answer:

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O : : C : : O

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Explanation:

8 0
3 years ago
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Order the levels of organization from the smallest (1) to the largest (4).
yKpoI14uk [10]

Answer:

cells=1

organ=3

organ system=4

tissue=2

Explanation:

i just did the question right now and i got them all correct.

3 0
4 years ago
Write the balanced equation for the complete combustion of hexane (C_6 H_12 0),with the correct states of matter.(5 pts)
elena55 [62]

Answer:

C6H12 (g)       +      9  O2 (g)           →         6 CO2 (g)          +          6  H2O (l)

Explanation:

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4 years ago
Magnesium reacts with hydrochloric acid (HCl) as follows. mc025-1.jpg How many milliliters of hydrogen gas are produced by the r
Juliette [100K]

Answer: 448 mL of hydrogen gas.

Solution:

Mg(s)+HCl(aq)\rightarrow MgCl_2(aq)_+H_2(g)

Now,according to reaction

1 mole of magnesium produces one mole of hydrogen gas.

Then 0.020 moles of magnesium will produce 0.020 moles of hydrogen gas.

Moles of H_ gas : 0.020 mol

At STP, 1 mol of gas occupies 22.4 L

So volume of 0.020 mol of H_2produced at STP :

= 22.4/times 0.020 = 0.448 L = 448 mL    (1L=1000mL)

8 0
4 years ago
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Write down as many correct, distinct, and relevant facts you can about the following prompt: 100 mL of 1.0 M solution H2SO4 is a
galben [10]

Answer:

Explanation:

From the equation:

H2SO4(aq) + 2NaOH(aq) --> Na2SO4(aq) + 2H2O (l)

<em>1 mole of the acid (H2SO4) and 2 moles of the base (NaOH) are required for complete neutralization.</em>

mole of acid (H2SO4) present = molarity x volume

                                  = 1 x 0.1 = 0.1 mole

Mole of base (NaOH)  present = mass/molar mass

                                                      = 7/40 = 0.175 mole

<em>The ratio of acid and base should be 1:2, hence the acid is slightly excessive in this case and the base is the limiting reagent that will determine the extent of the reaction.</em>

Amount of excess acid = 0.1 - 0.175/2

                                       = 0.0125 mole

volume of excess acid = mole/molarity

                                      = 0.0125 x 1 = 0.0125 L

                                       = 12.5 mL

<em>Hence, the acid (H2SO4) was in excess by 12.5 mL.</em>

8 0
3 years ago
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